Java Utililty Methods Byte Array And

byte[] and(byte[] a, byte[] b)
a & b

if (a == null)
 throw new IllegalArgumentException("a should not be null");
if (b == null)
 throw new IllegalArgumentException("b should not be null");
if (a.length != b.length)
 throw new IllegalArgumentException("byte array length should be same");
int len = a.length;
byte[] result = new byte[len];
...

byte[] and(byte[] a, byte[] b)
and

byte[] dst = new byte[a.length];
and(a, 0, b, 0, dst, 0, dst.length);
return dst;

byte[] and(byte[] a, byte[] b)
and

if (a.length != b.length) {
 throw new IllegalArgumentException("Arrays a and b should have equal length");
byte[] result = new byte[a.length];
for (int i = 0; i < a.length; i++) {
 result[i] = (byte) (a[i] & b[i]);
return result;
...

void and(byte[] a, int offsetA, byte[] b, int offsetB, byte[] dst, int dstOffset, int length)
AND length number of bytes from a with b using the syntax ( a[i] & b[i] ) and store the result in dst

for (int i = 0, aI = offsetA, bI = offsetB, dstI = dstOffset; i < length; i++, aI++, bI++, dstI++) {
 dst[dstI] = (byte) (a[aI] & b[bI]);

byte[] and(byte[] data1, byte[] data2)
and

if (data1.length != data2.length) {
 throw new IllegalArgumentException(
 "array lenth does NOT match, " + data1.length + " vs " + data2.length);
final byte r[] = new byte[data1.length];
for (int i = 0; i < r.length; i++) {
 r[i] = (byte) (data1[i] & data2[i]);
return r;