Java Utililty Methods Bit Get

int bitAt(byte b, int pos)
bit At

int i = 1 << 7 - pos;
return (b & i & 0xFF) > 0 ? 1 : 0;

boolean bitAt(int offset, byte aByte)
Examine the values of bits within a byte.

return (aByte & (1 << offset)) != 0;

boolean bitAt(int offset, byte aByte)
bit At

return (aByte & (1 << offset)) != 0;

int bits(int i)
bits

return 32 - Integer.numberOfLeadingZeros(i);

int bits(int i)
Compute the integer logarithms (ceil(log(x+1)) of a value

return 32 - Integer.numberOfLeadingZeros(i);

int bits(int n, int offset, int length)
Bit play
http://stackoverflow.com/questions/11419501/converting-bits-in-to-integer

n = n >> (31 - offset - length);
int mask = ~(-1 << length);
return n & mask;

String bits(int value, int c)
bits

StringBuffer sb = new StringBuffer();
for (int i = c - 1; i >= 0; i--) {
 int bv = (value >>> (8 * i)) & 0xff;
 sb.append('[');
 for (int j = 7; j >= 0; j--) {
 sb.append((bv & (1 << j)) > 0 ? '1' : '0');
 sb.append(']');
...

int bits(int value, int first, int last)
Get the specified bits from the specified value.

return (value >> last) & mask(first - last + 1);

int bits(long maxValue)
bits

int bits = 0;
while (maxValue != 0) {
 bits++;
 maxValue >>>= 1;
return bits;

long bits(long value, int sb, int eb)
Extracts a bit range from a long value

value >>>= eb;
sb -= eb - 1;
long mask = (1L << sb) - 1;
value &= mask;
return value;