The list of methods to do Array Min Value are organized into topic(s).
int
argmin(double... vs) argmin
double min = vs[0];
int minI = 0;
for (int i = 1; i < vs.length; i++) {
double v = vs[i];
if (v < min) {
min = v;
minI = i;
return minI;
int
argmin(final double[] vec) Returns the index of the smallest element in a vector.
assert vec != null;
double min = vec[0];
int argmin = 0;
for (int i = 1; i < vec.length; i++) {
final double tmp = vec[i];
if (tmp < min) {
min = tmp;
argmin = i;
...
int
argmin(int[] a) argmin
int re = Integer.MAX_VALUE;
int arg = -1;
for (int i = 0; i < a.length; i++) {
if (a[i] < re) {
re = a[i];
arg = i;
return arg;
int
argMin(int[] a) arg Min
int v = Integer.MAX_VALUE;
int ind = -1;
for (int i = 0; i < a.length; i++) {
if (a[i] < v) {
v = a[i];
ind = i;
return ind;
double[]
arrayMin(double minVal, double[] vals) Applies a min value to all elements in an array
double[] out = new double[vals.length];
for (int i = 0; i < vals.length; i++) {
out[i] = Math.min(minVal, vals[i]);
return out;
double
arrayMin(double[] arr) A method to find min element in an array of doubles.
double min = Double.POSITIVE_INFINITY;
for (double cur : arr)
min = Math.min(min, cur);
return min;
double
arrayMin(double[] x) array Min
if (x.length == 0) {
throw new IllegalArgumentException();
double result = x[0];
for (int i = 1; i < x.length; i++) {
if (result > x[i]) {
result = x[i];
return result;
int
arrayMin(int[] property) array Min
int[] copy = property.clone();
int min = 0;
int numElements = copy.length;
Arrays.sort(copy);
if (numElements > 0)
min = copy[0];
return min;
float
findMin(float[] array) Finds minimal element in array
float min = Float.MAX_VALUE;
for (int i = 0; i < array.length; i++) {
if (array[i] < min) {
min = array[i];
return min;