int
argmax(double[] array, boolean naturalNumbers) Returns the index of the maximal value in a double[]
int best = -1;
double value = (naturalNumbers) ? 0D : Double.MIN_VALUE;
for (int i = 0; i < array.length; ++i) {
if (array[i] > value) {
value = array[i];
best = i;
return best;
int
argmax(double[] weights) argmax
if (weights == null)
return -1;
if (weights.length == 1)
return 0;
double max = weights[0];
int maxI = 0;
for (int i = 1; i < weights.length; i++)
if (weights[i] > max)
...
int
argmax(final double[] vec) Returns the index of the greatest element in a vector.
assert (vec != null);
double max = vec[0];
int argmax = 0;
for (int i = 1; i < vec.length; i++) {
final double tmp = vec[i];
if (tmp > max) {
max = tmp;
argmax = i;
...
int
argmax(float[] args) argmax
int result = 0;
for (int i = 1; i < args.length; i++) {
if (Float.compare(args[result], args[i]) < 0)
result = i;
return result;
int
argMax(int[] a) arg Max
int v = Integer.MIN_VALUE;
int ind = -1;
for (int i = 0; i < a.length; i++) {
if (a[i] > v) {
v = a[i];
ind = i;
return ind;
int
argmax(int[] a) argmax
int re = Integer.MIN_VALUE;
int arg = -1;
for (int i = 0; i < a.length; i++) {
if (a[i] > re) {
re = a[i];
arg = i;
return arg;
int
argmax(int[] array) Returns the index of the max value in the specified array
int index = -1;
int max = Integer.MIN_VALUE;
for (int i = 0; i < array.length; i++) {
if (array[i] > max) {
max = array[i];
index = i;
return index;
int
argmax(int[] input) Returns the index of the largest element in an array.
int i = input.length - 1;
int currentMaximum = input[i];
int currentArgmax = i;
while (i >= 0) {
if (input[i] > currentMaximum) {
currentMaximum = input[i];
currentArgmax = i;
i++;
return currentArgmax;
double[]
arrayMax(double maxVal, double[] vals) Applies a max value to all elements in an array
double[] out = new double[vals.length];
for (int i = 0; i < vals.length; i++) {
out[i] = Math.max(maxVal, vals[i]);
return out;