-- DavidLambert 2007年07月18日 15:08:31
'''
$ python
Python 2.5.1 (r251:54863, Jun 25 2007, 14:55:49)
[GCC 3.4.4 (cygming special) (gdc 0.12, using dmd 0.125)] on cygwin
Type "help", "copyright", "credits" or "license" for more information.
>>>
'''
x = 'abc'
expect = 'abcabcabc'
class C(object):
def f(x):
return x*3
__call__ = staticmethod(f)
assert expect == C()(x) # works great
# straightforward from docs
E = type('E',(object,),dict(__call__=staticmethod(C.__call__)))
assert expect == E()(x) # works great, why must I
# repeat staticmethod?
def f(x):
return x*3
class G(object):
__call__ = staticmethod(f)
assert expect == G()(x) # works great, works as I expect
# My opportunity to make a static method has passed?
I = type('I',(C,),dict(__call__ = staticmethod(C.f)))
try:
assert expect == I()(x)
except TypeError,info: # I don\'t understand.
assert info.message.startswith('unbound method f()')
# Staticness lost?
F = type('F',(object,),dict(__call__=C.__call__))
try:
assert expect == F()(x)
except TypeError,info: # misunderstood,
assert info.message.startswith('f() takes exactly 1 argument (2 given)')