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Go的函数参数总是传值

caiyang101 · · 1804 次点击 · · 开始浏览
这是一个创建于 的文章,其中的信息可能已经有所发展或是发生改变。

As in all languages in the C family, everything in Go is passed by value. That is, a function always gets a copy of the thing being passed, as if there were an assignment statement assigning the value to the parameter. For instance, passing an int value to a function makes a copy of the int, and passing a pointer value makes a copy of the pointer, but not the data it points to. (See alater sectionfor a discussion of how this affects method receivers.)

Map and slice values behave like pointers: they are descriptors that contain pointers to the underlying map or slice data. Copying a map or slice value doesn't copy the data it points to. Copying an interface value makes a copy of the thing stored in the interface value. If the interface value holds a struct, copying the interface value makes a copy of the struct. If the interface value holds a pointer, copying the interface value makes a copy of the pointer, but again not the data it points to.

以下是测试代码,结果贴在下面,不解释了。

packagemain
import(
"fmt"
"reflect"
"unsafe"
)
funcprintInt(iint) {
 fmt.Printf("int i: %p\n", &i)
}
funcprintInt2(i *int) {
 fmt.Printf("int i: %p\n", i)
}
funcprintStr(sstring) {
 fmt.Printf("string s: %p\n", &s)
 hdr := (*reflect.StringHeader)(unsafe.Pointer(&s))
 data := hdr.Data
 fmt.Printf("string s data: 0x%x\n", data)
}
funcprintStr2(s *string) {
 fmt.Printf("string s: %p\n", s)
 hdr := (*reflect.StringHeader)(unsafe.Pointer(s))
 data := hdr.Data
 fmt.Printf("string s data: 0x%x\n", data)
}
funcprintSlice(s []int) {
 fmt.Printf("slice s: %p\n", &s)
 hdr := (*reflect.SliceHeader)(unsafe.Pointer(&s))
 data := hdr.Data
 fmt.Printf("slice s data: 0x%x\n", data)
}
funcprintSlice2(s *[]int) {
 fmt.Printf("slice s: %p\n", s)
 hdr := (*reflect.SliceHeader)(unsafe.Pointer(s))
 data := hdr.Data
 fmt.Printf("slice s data: 0x%x\n", data)
}
typeSstruct{
 I int
}
funcprintStruct(s S) {
 fmt.Printf("struct s: %p, I: %p\n", &s, &(s.I))
}
funcprintStruct2(s *S) {
 fmt.Printf("struct s: %p, I: %p\n", &s, &(s.I))
}
funcprintInterface(iinterface{}) {
 fmt.Printf("int i: %p\n", &i)
}
funcprintInterface2(iinterface{}) {
 s := i.(S)
 fmt.Printf("struct s: %p, I: %p\n", &s, &(s.I))
}
funcprintInterface3(iinterface{}) {
 s := i.(*S)
 fmt.Printf("struct s: %p, I: %p\n", s, &(s.I))
}
funcmain() {
//test int
 i :=10
 fmt.Printf("int i: %p\n", &i)
 printInt(i)
 printInt2(&i)
//test string
 s := "hello, world"
 fmt.Printf("\n\nstring s: %p\n", &s)
 hdr := (*reflect.StringHeader)(unsafe.Pointer(&s))
 data := hdr.Data
 fmt.Printf("string s data: 0x%x\n", data)
 printStr(s)
 printStr2(&s)
//slice and map
 sl := []int{1,2,3,4,5}
 fmt.Printf("\n\nslice s: %p\n", &sl)
 hdr2 := (*reflect.SliceHeader)(unsafe.Pointer(&sl))
 data = hdr2.Data
 fmt.Printf("slice s data: 0x%x\n", data)
 printSlice(sl)
 printSlice2(&sl)
//struct
 ss := S{I:10}
 ssp := &ss
 fmt.Printf("\n\nstruct s: %p, I: %p\n", ssp, &(ss.I))
 printStruct(ss)
 printStruct2(ssp)
//interface to int
 fmt.Printf("\n\nint i: %p\n", &i)
 printInterface(i)
//interface to struct
 fmt.Printf("\n\nstruct s: %p, I: %p\n", ssp, &(ss.I))
 printInterface2(ss)
 printInterface3(ssp)
}

输出结果:

inti:0xc420074188
inti:0xc4200741b8
inti:0xc420074188
string s: 0xc4200741c0
string s data: 0xa778d
string s: 0xc4200741e0
string s data: 0xa778d
string s: 0xc4200741c0
string s data: 0xa778d
slice s: 0xc42006e0c0
slice s data: 0xc4200780c0
slice s: 0xc42006e0e0
slice s data: 0xc4200780c0
slice s: 0xc42006e0c0
slice s data: 0xc4200780c0
struct s: 0xc420074210, I:0xc420074210
struct s: 0xc420074218, I:0xc420074218
struct s: 0xc420084020, I:0xc420074210
inti:0xc420074188
inti:0xc420074230
struct s: 0xc420074210, I:0xc420074210
struct s: 0xc420074228, I:0xc420074228
struct s: 0xc420074210, I:0xc420074210

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本文来自:CSDN博客

感谢作者:caiyang101

查看原文:Go的函数参数总是传值

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