简单测试一下go(golang)和libtask协程的切换效率

简单测试一下go(golang)和libtask协程的切换效率, libtask一个C语言的协程库,是go语言的前身很早期的原型,

测试机器是我的mac air 安装的centos虚拟机(只有一个核)

代码没有采用任何优化,只是使用默认配置

测试结论:

golang 切换100w次 需要 295ms

libtask 切换100w次 需要1446ms

package main
import (
 "fmt"
 "runtime"
 "time"
 )
var i int = 0
func test(){
	for{
		i++
		if i >1000000{
			fmt.Printf("end switch \n")
			break
		}else{
			//fmt.Printf(" in test i:%d \n", i)
		}
		runtime.Gosched()
	}
}
func main(){
	fmt.Printf("GOMAXPROCS :%d \n",runtime.GOMAXPROCS(1))
	tv1 := time.Now().UnixNano()
	go test()
	// in main goroutine
	test()
	tv2 := time.Now().UnixNano()
	usetime := (tv2 - tv1)/1000000
	fmt.Printf("use time: %dms \n", usetime)
	fmt.Printf("end main \n")
}

#include <stdio.h>
#include <string.h>
#include <errno.h>
#include <unistd.h>
#include <stdlib.h>
#include <task.h>
#include<sys/time.h>
extern int tasknswitch;
enum { STACK = 32768 };
int i = 0;
struct timeval tv1, tv2;
void
testswitch(void *v)
{
 int ms;
 while(1)
 {
	 i++;
	 if( i< 1000000)
	 {
	 //printf("int task i:%d \n", i);
	 taskyield();
	 }
	 else
	 { 
	 // chansendul(c, 0);
	 //taskexitall(0);
	 gettimeofday(&tv2,NULL);
 ms = ((tv2.tv_sec - tv1.tv_sec)*1000000 + (tv2.tv_usec - tv1.tv_usec))/1000;
 printf("time use %d\n ", ms);
 printf("task swithch %d \n", tasknswitch);
	 taskexitall(0); 
	 }
 }
}
void
taskmain(int argc, char **argv)
{
 	int n;
	//c = chancreate(sizeof(unsigned long), 0);
 	gettimeofday(&tv1, NULL);
	//for(i=1; i<; i++){
	taskcreate(testswitch, 0, STACK);
	//}
 testswitch(NULL);
}

本文来自:CSDN博客

感谢作者:mumumuwudi

查看原文:简单测试一下go(golang)和libtask协程的切换效率

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