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Based on this MDN reference:

\s
Matches a single white space character, including space, tab, form feed, line feed and other Unicode spaces. Equivalent to [ \f\n\r\t\v​\u00a0\u1680​\u180e\u2000​-\u200a​\u2028\u2029\u202f\u205f​\u3000\ufeff].

And on ECMA 262 reference, saying \s should match "White Space" like \u0009 (Tab, <TAB>), \u000B (Vertical Tab, <VT>), \u000C (Form Feed, <FF>), \u0020 (Space, <SP>), \u00A0 (No-break space, <NBSP>), \uFEFF (Byte Order Mark, <BOM>), and other category "Zs" (<USP>), and also "line terminators" like \u000A (Line Feed, <LF>), \u000D (Carriage Return, <CR>), \u2028 (Line separator, <LS>) and \u2029 (Paragraph separator, <PS>), you can use the following code to remove elements that are either empty or whitespace only if trim() is not natively available:

var arr = ['Apple', ' ', 'Mango', '', 'Banana', ' ', 'Strawberry'];
arr = arr.filter(s => s.replace(/\s+/g, '').length !== 0);
// Or for ES5
// arr = arr.filter(function (el) { return el.replace(/\s+/g, '').length !== 0; });
console.log(arr);

In case some old browsers behave differently with \s, replace it with [ \f\n\r\t\v​\u00a0\u1680​\u180e\u2000​-\u200a​\u2028\u2029\u202f\u205f​\u3000\ufeff] character class:

arr = arr.filter(function (el) { return el.replace(/[ \f\n\r\t\v​\u00a0\u1680​\u180e\u2000​-\u200a​\u2028\u2029\u202f\u205f​\u3000\ufeff]+/g, '').length !== 0; });

And you can also customize it further to include new Unicode spaces to come.