Check if an element contains a class in JavaScript?

Question

Using plain JavaScript (not jQuery), Is there any way to check if an element contains a class?

Currently, I'm doing this:

var test = document.getElementById("test");
var testClass = test.className;
switch (testClass) {
 case "class1":
 test.innerHTML = "I have class1";
 break;
 case "class2":
 test.innerHTML = "I have class2";
 break;
 case "class3":
 test.innerHTML = "I have class3";
 break;
 case "class4":
 test.innerHTML = "I have class4";
 break;
 default:
 test.innerHTML = "";
}

<div id="test" class="class1"></div>

The issue is that if I change the HTML to this...

<div id="test" class="class1 class5"></div>

...there's no longer an exact match, so I get the default output of nothing (""). But I still want the output to be I have class1 because the <div> still contains the .class1 class.

• Ronnie Smith: element.classList.contains(cls)
• shasi kanth: document.getElementsByClassName('class1').length

Answer 1

Use element.classList .contains method:

element.classList.contains(class);

This works on all current browsers and there are polyfills to support older browsers too.

---

Alternatively, if you work with older browsers and don't want to use polyfills to fix them, using indexOf is correct, but you have to tweak it a little:

function hasClass(element, className) {
 return (' ' + element.className + ' ').indexOf(' ' + className+ ' ') > -1;
}

Otherwise you will also get true if the class you are looking for is part of another class name.

DEMO

jQuery uses a similar (if not the same) method.

---

Applied to the example:

As this does not work together with the switch statement, you could achieve the same effect with this code:

var test = document.getElementById("test"),
 classes = ['class1', 'class2', 'class3', 'class4'];
test.innerHTML = "";
for(var i = 0, j = classes.length; i < j; i++) {
 if(hasClass(test, classes[i])) {
 test.innerHTML = "I have " + classes[i];
 break;
 }
}

It's also less redundant ;)

• daGUY: Awesome, but how do I use that in combination with the switch statement so that I can change the output based on which classes the div contains?
• Felix Kling: @daGUY: What do you want to do with the switch statement anyway? E.g. The second div has two classes but it would only output I have class1 as you are using break. If you want to output every class an element has, then you can just take the className and split it on white spaces. Or what is your actual goal?
• CodeToad: FYI: for svg elements, in browsers such as a safari, className is not a string but an object of type svganimatedstring. Checking the class attribute rather than className is currently the most cross-browser way to check class if you are working with svg elements.
• Ced: Is there a specific reason why you added spaces before and after?
• Felix Kling: @KayceBasques: because we also add spaces to cls so that we only match full class names. hasClass(element, 'foo') should not match for class foobar. And if we didn't add spaces to element.className we could never match the first or last class names.

Answer 2

The easy and effective solution is trying .contains method.

test.classList.contains(testClass);

Answer 3

In modern browsers, you can just use the contains method of Element.classList :

testElement.classList.contains(className)

---

Demo

var testElement = document.getElementById('test');
console.log({
 'main' : testElement.classList.contains('main'),
 'cont' : testElement.classList.contains('cont'),
 'content' : testElement.classList.contains('content'),
 'main-cont' : testElement.classList.contains('main-cont'),
 'main-content' : testElement.classList.contains('main-content'),
 'main main-content' : testElement.classList.contains('main main-content')
});

<div id="test" class="main main-content content"></div>

---

Supported browsers

enter image description here

(from CanIUse.com)

---

Polyfill

If you want to use Element.classList but you also want to support older browsers, consider using this polyfill by Eli Grey.

Answer 4

This question is pretty solidly answered by element.classList.contains(), but people got pretty extravagant with their answers and made some bold claims, so I ran a benchmark.

Remember that each test is doing 1000 iterations, so most of these are still very fast. Unless you rely extensively on this for a specific operation, you won't see a performance difference.

I ran some tests with basically every way to do this. On my machine, (Win 10, 24gb, i7-8700), classList.contains performed super well. So did className.split(' ') which is effectively the same.

The winner though is classList.contains(). If you're not checking for classList to be undefined, ~(' ' + v.className + ' ').indexOf(' ' + classToFind + ' ') creeps ahead 5-15%

enter image description here

Answer 5

Element.matches()

element.matches(selectorString)

According to MDN Web Docs:

The Element.matches() method returns true if the element would be selected by the specified selector string; otherwise, returns false.

Therefore, you can use Element.matches() to determine if an element contains a class.

const element = document.querySelector('#example');
console.log(element.matches('.foo')); // true

<div id="example" class="foo bar"></div>

View Browser Compatibility

• kasimir: Seems cleaner and less cumbersome to me, though I'm curious how this compares in terms of performance.
• Regular Jo: @kasimir .matches is 3-4x slower. jsben.ch/iKweE

Answer 6

Since he wants to use switch(), I'm surprised no one has put this forth yet:

var test = document.getElementById("test");
var testClasses = test.className.split(" ");
test.innerHTML = "";
for(var i=0; i<testClasses.length; i++) {
 switch(testClasses[i]) {
 case "class1": test.innerHTML += "I have class1<br/>"; break;
 case "class2": test.innerHTML += "I have class2<br/>"; break;
 case "class3": test.innerHTML += "I have class3<br/>"; break;
 case "class4": test.innerHTML += "I have class4<br/>"; break;
 default: test.innerHTML += "(unknown class:" + testClasses[i] + ")<br/>";
 }
}

• Silver Ringvee: I was just wondering the same thing, but yes, that's the closest to the original problem!

Answer 7

Here is a little snippet If you’re trying to check wether element contains a class, without using jQuery.

function hasClass(element, className) {
 return element.className && new RegExp("(^|\\s)" + className + "(\\s|$)").test(element.className);
}

This accounts for the fact that element might contain multiple class names separated by space.

OR

---

You can also assign this function to element prototype.

Element.prototype.hasClass = function(className) {
 return this.className && new RegExp("(^|\\s)" + className + "(\\s|$)").test(this.className);
};

And trigger it like this (very similar to jQuery’s .hasClass() function):

document.getElementById('MyDiv').hasClass('active');

• scottlimmer: I prefer this solution more. It avoids the issue of the class name partially matching another class and doesn't require polyfills to work in IE.

Answer 8

A simplified oneliner:¹

function hasClassName(classname,id) {
 return String ( ( document.getElementById(id)||{} ) .className )
 .split(/\s/)
 .indexOf(classname) >= 0;
}

¹ indexOf for arrays is not supported by IE (ofcourse). There are plenty of monkey patches to be found on the net for that.

Answer 9

This is a little old, but maybe someone will find my solution helpfull:

// Fix IE's indexOf Array
if (!Array.prototype.indexOf) {
 Array.prototype.indexOf = function (searchElement) {
 if (this == null) throw new TypeError();
 var t = Object(this);
 var len = t.length >>> 0;
 if (len === 0) return -1;
 var n = 0;
 if (arguments.length > 0) {
 n = Number(arguments[1]);
 if (n != n) n = 0;
 else if (n != 0 && n != Infinity && n != -Infinity) n = (n > 0 || -1) * Math.floor(Math.abs(n));
 }
 if (n >= len) return -1;
 var k = n >= 0 ? n : Math.max(len - Math.abs(n), 0);
 for (; k < len; k++) if (k in t && t[k] === searchElement) return k;
 return -1;
 }
}
// add hasClass support
if (!Element.prototype.hasClass) {
 Element.prototype.hasClass = function (classname) {
 if (this == null) throw new TypeError();
 return this.className.split(' ').indexOf(classname) === -1 ? false : true;
 }
}

• Rafael Herscovici: use: 'element.hasClass('classname')
• Vitor Canova: Why did you use t.length >>> 0 ? As far as I know it is a noop if you use '0', right?
• pqsk: wow so much code for something simple. Why not use a regular expression and not reinvent the wheel? you could just use /^class_name_you_are_searching_for$/.test(myElement.className)
• pqsk: I wrote that too fast. Just to not overcomplicate my regular expression it would be /\s*class_name_you_are_searching_for\s*/.test(myElement.className)
• Rafael Herscovici: @pqsk - i write my own libraries for future use. and this just adds to my stack. of course other solutions would work, this is just my prefered way

Answer 10

I know there a lot of answers but most of these are for additional functions and additional classes. This is the one I personally use; much cleaner and much less lines of code!

if( document.body.className.match('category-page') ) { 
 console.log('yes');
}

• hooblei: this method may return false positives when searching for a class name that partially matches - e.g.<body class="category-page"> and document.body.className.match('page') - will match but there is no class page attached to the element
• Andrew: Can be resolved with \b, e.g. /\bpage\b/g, since it's regex (note: have to use / /g).

Answer 11

className is just a string so you can use the regular indexOf function to see if the list of classes contains another string.

• Felix Kling: What about testing for class class in the above example?
• Zirak: From experience, this method can be quite risky: It will return true when you look for the class foo on an element which has the foobar class.
• David: Sure, you just have be aware of what you are testing. Felix's code works well by using spaces as the delimiter.
• Anthony Rutledge: Fails to account for nested instances of a class name. Example: 'end' can be found in the class name 'frontend'.

Answer 12

To check if an element contains a class, you use the contains() method of the classList property of the element:*

element.classList.contains(className);

*Suppose you have the following element:

<div class="secondary info">Item</div>*

To check if the element contains the secondary class, you use the following code:

 const div = document.querySelector('div');
 div.classList.contains('secondary'); // true

The following returns false because the element doesn’t have the class error:

 const div = document.querySelector('div');
 div.classList.contains('error'); // false

Answer 13

I've created a prototype method which uses classList, if possible, else resorts to indexOf:

Element.prototype.hasClass = Element.prototype.hasClass || 
 function(classArr){
 var hasClass = 0,
 className = this.getAttribute('class');
 
 if( this == null || !classArr || !className ) return false;
 
 if( !(classArr instanceof Array) )
 classArr = classArr.split(' ');
 for( var i in classArr )
 // this.classList.contains(classArr[i]) // for modern browsers
 if( className.split(classArr[i]).length > 1 ) 
 hasClass++;
 return hasClass == classArr.length;
};
///////////////////////////////
// TESTS (see browser's console when inspecting the output)
var elm1 = document.querySelector('p');
var elm2 = document.querySelector('b');
var elm3 = elm1.firstChild; // textNode
var elm4 = document.querySelector('text'); // SVG text
console.log( elm1, ' has class "a": ', elm1.hasClass('a') );
console.log( elm1, ' has class "b": ', elm1.hasClass('b') );
console.log( elm1, ' has class "c": ', elm1.hasClass('c') );
console.log( elm1, ' has class "d": ', elm1.hasClass('d') );
console.log( elm1, ' has class "a c": ', elm1.hasClass('a c') );
console.log( elm1, ' has class "a d": ', elm1.hasClass('a d') );
console.log( elm1, ' has class "": ', elm1.hasClass('') );
console.log( elm2, ' has class "a": ', elm2.hasClass('a') );
// console.log( elm3, ' has class "a": ', elm3.hasClass('a') );
console.log( elm4, ' has class "a": ', elm4.hasClass('a') );

<p class='a b c'>This is a <b>test</b> string</p>
<svg xmlns="http://www.w3.org/2000/svg" width="100px" height="50px">
 <text x="10" y="20" class='a'>SVG Text Example</text>
</svg>

Test page

• Ced: Is there a reason why you'd want to use classlist instead of index of e.className? Seems like the perf are less good
• vsync: @Ced - well, perf is irrelevant if you're not testing thousands of elements for their class, (it will probably be refactored in browsers in the future). it's more elegant to use because the code describes its functionality, but bottom line, it doesn't matter, do whatever you want :)

Answer 14

Here's a case-insensitive trivial solution:

function hasClass(element, classNameToTestFor) {
 var classNames = element.className.split(' ');
 for (var i = 0; i < classNames.length; i++) {
 if (classNames[i].toLowerCase() == classNameToTestFor.toLowerCase()) {
 return true;
 }
 }
 return false;
}

Answer 15

1. Felix's trick of adding spaces to flank the className and the string you're searching for is the right approach to determining whether the elements has the class or not.

2. To have different behaviour according to the class, you may use function references, or functions, within a map:

   function fn1(element){ /* code for element with class1 */ }
   function fn2(element){ /* code for element with class2 */ }
   function fn2(element){ /* code for element with class3 */ }
   var fns={'class1': fn1, 'class2': fn2, 'class3': fn3};
   for(var i in fns) {
    if(hasClass(test, i)) {
    fns[i](test);
    }
   }
   

   • for(var i in fns) iterates through the keys within the fns map.
   • Having no break after fnsi allows the code to be executed whenever there is a match - so that if the element has, f.i., class1 and class2, both fn1 and fn2 will be executed.
   • The advantage of this approach is that the code to execute for each class is arbitrary, like the one in the switch statement; in your example all the cases performed a similar operation, but tomorrow you may need to do different things for each.
   • You may simulate the default case by having a status variable telling whether a match was found in the loop or not.

Answer 16

I would Poly fill the classList functionality and use the new syntax. This way newer browser will use the new implementation (which is much faster) and only old browsers will take the performance hit from the code.

https://github.com/remy/polyfills/blob/master/classList.js

Answer 17

If the element only has one class name you can quickly check it by getting the class attribute. The other answers are much more robust but this certainly has it's use cases.

if ( element.getAttribute('class') === 'classname' ) {
}

Answer 18

See this Codepen link for faster and easy way of checking an element if it has a specific class using vanilla JavaScript~!

hasClass (Vanilla JS)

function hasClass(element, cls) {
 return (' ' + element.className + ' ').indexOf(' ' + cls + ' ') > -1;
}

Answer 19

This is supported on IE8+.

First we check if classList exists if it does we can use the contains method which is supported by IE10+. If we are on IE9 or 8 it falls back to using a regex, which is not as efficient but is a concise polyfill.

if (el.classList) {
 el.classList.contains(className);
} else {
 new RegExp('(^| )' + className + '( |$)', 'gi').test(el.className);
}

Alternatively if you are compiling with babel you can simply use: el.classList.contains(className);

Answer 20

I think that perfect solution will be this

if ($(this).hasClass("your_Class")) 
 alert("positive"); 
else 
 alert("Negative");

• nkmol: 1. "Using plain JavaScript (not jQuery)" 2. Use brackets
• TheBlackBenzKid: 3 - use Parenthesis

Answer 21

This is a bit off, but if you have an event that triggers switch, you can do without classes:

<div id="classOne1"></div>
<div id="classOne2"></div>
<div id="classTwo3"></div>

You can do

$('body').click( function() {
 switch ( this.id.replace(/[0-9]/g, '') ) {
 case 'classOne': this.innerHTML = "I have classOne"; break;
 case 'classTwo': this.innerHTML = "I have classTwo"; break;
 default: this.innerHTML = "";
 }
});

.replace(/[0-9]/g, '') removes digits from id.

It is a bit hacky, but works for long switches without extra functions or loops

Answer 22

Using the classList is also ideal

HTML

<div id="box" class="myClass"></div>

JavaScript

const element = document.querySelector("#box");
element.classList.contains("myClass");

Answer 23

Try this one:

document.getElementsByClassName = function(cl) {
 var retnode = [];
 var myclass = new RegExp('\\b'+cl+'\\b');
 var elem = this.getElementsByTagName('*');
 for (var i = 0; i < elem.length; i++) {
 var classes = elem[i].className;
 if (myclass.test(classes)) retnode.push(elem[i]);
 }
 return retnode;
};

• Felix Kling: Be careful with the word boundary. It will also match true if you have e.g. a class foo-bar and search for foo.
• Stano: Hi Jimy, so I was searching for this \b metacharacter and it only considers [a-zA-Z0-9_] as word characters. So for a classnames containing a minus char this won't work.

Answer 24

in which element is currently the class '.bar' ? Here is another solution but it's up to you.

var reg = /Image/g, // regexp for an image element
query = document.querySelector('.bar'); // returns [object HTMLImageElement]
query += this.toString(); // turns object into a string
if (query.match(reg)) { // checks if it matches
 alert('the class .bar is attached to the following Element:\n' + query);
}

jsfiddle demo

Of course this is only a lookup for 1 simple element <img>(/Image/g) but you can put all in an array like <li> is /LI/g, <ul> = /UL/g etc.

Answer 25

Just to add to the answer for people trying to find class names within inline SVG elements.

Change the hasCLass() function to:

function hasClass(element, cls) {
 return (' ' + element.getAttribute('class') + ' ').indexOf(' ' + cls + ' ') > -1;
 }

Instead of using the className property you'll need to use the getAttribute() method to grab the class name.

Answer 26

I created these functions for my website, I use only vanilla javascript, maybe it will help someone. First I created a function to get any HTML element:

//return an HTML element by ID, class or tag name
 var getElement = function(selector) {
 var elements = [];
 if(selector[0] == '#') {
 elements.push(document.getElementById(selector.substring(1, selector.length)));
 } else if(selector[0] == '.') {
 elements = document.getElementsByClassName(selector.substring(1, selector.length));
 } else {
 elements = document.getElementsByTagName(selector);
 }
 return elements;
 }

Then the function that recieve the class to remove and the selector of the element:

var hasClass = function(selector, _class) {
 var elements = getElement(selector);
 var contains = false;
 for (let index = 0; index < elements.length; index++) {
 const curElement = elements[index];
 if(curElement.classList.contains(_class)) {
 contains = true;
 break;
 }
 }
 return contains;
 }

Now you can use it like this:

hasClass('body', 'gray')
hasClass('#like', 'green')
hasClass('.button', 'active')

Hope it will help.

Answer 27

Tip: Try to remove dependencies of jQuery in your projects as much as you can - VanillaJS.

document.firstElementChild returns <html> tag then the classList attribute returns all classes added to it.

if(document.firstElementChild.classList.contains("your-class")){
 // <html> has 'your-class'
} else {
 // <html> doesn't have 'your-class'
}

Answer 28

Since .className is a string, you can use the string includes() method to check if your .className includes your class name:

element.className.includes("class1")

Answer 29

As the accepted answer suggests, Element.className returns a string, so you can easily check if a class exists by using the indexOf() method:

element.className.indexOf('animated') > -1

If you are interested in the performance difference between indexOf vs classList.contains, using indexOf seems to be slightly faster. I did a quick benchmark performance test to check that. Here are my findings: ClassName.indexOf vs ClassList.contains.

Answer 30

For me the most elegant and faster way to achieve it is:

function hasClass(el, cl) {
 return el.classList ? el.classList.contains(cl) : !!el.className && !!el.className.match(new RegExp('(?: |^)' + cl + '(?: |$)'));
 }

enter image description here

• Regular Jo: First, that regex isn't totally reliable, or efficient. The (capturing group) is unnecessary. You should use (?: |^)c'+i+'(?: |$). Second, this is far from the fastest. jsben.ch/QAOQs
• GSite: @RegularJo I run your test, but it results to me that regex is the fastest
• GSite: @RegularJo also the "c" in your regex is wrong, the correct regex is '(?: |^)'+i+'(?: |$)'
• Regular Jo: Lol, yep, forgot to update my regex from the test to change the c back.