c++ How to convert string array to char array

Question

my program should have store = 5 string values - Simpsun GN120, Sonic Lux10, Ultimax G42, Antalpha A200 and Nickov N230 and then make a calculation that will make code for each value. Code would take first 3 letters and 3 last letters of a value.

first code from value: Simpsun GN120

would look like this: Sim120

my biggest issue was that i couldn't make a string array as getting a length of each value in array would crash a program so for now i have made program that will do this calculation but only if string is not array if someone could give me some tips how i could improve my code to make that string in to array

#include <iostream>
using namespace std;
int main()
{
 string str = "Simpsun GN120";
 int i;
 string productCode[5];
 for (i = 0; i < str.length(); i++)
 {
 if (i == 0 || i == 1 || i == 2)
 {
 productCode[0] += str[i];
 }
 if (i == str.length() - 1 || i == str.length() - 2 || i == str.length() - 3)
 {
 productCode[0] += str[i];
 }
 }
 cout << productCode[0];
}

• sYsTeM: Possible duplicate of How to convert string to char array in C++?
• jignatius: productCode[0] = str.substr(0, 3) + str.substr(str.length() - 3)
• N0way1998: well i can convert string to char array and so on but the problem is i would like to make that line string str = "Simpsun GN120"; in to array which would look like this string str[5] = {"Simpsun GN120", "Sonic Lux10", "Ultimax G42", "Antalpha A200", "Nickov N230" }; well ofc later on i will change my string array that won't have assign constant size and it will expand as i will have to input each name and store it in array like "Simpsun GN120" and so on.
• N0way1998: my current code is working but as i said above only with normal string because if i would like to make string array for str .length wouldn't work to check size of each name in array as i will have to make code for each name individually
• N0way1998: whats does substr mean? productCode[0] = str.substr(0, 3) + str.substr(str.length() - 3); @jignatius

Answer 1

It's simple using string class .Run a loop to execute productCode[i] = str[i].substr(0, 3) + str[i].substr(str[i].length() - 3); and your work is done.

Answer 2

jignatius Thank you very much for that answer!

using namespace std;
int main()
{
 string str[2] = { "Simpsun GN120", "Sonic Lux10" };
 int i;
 string productCode[5];
 for (int i = 0; i < 2; i++)
 {
 productCode[i] = str[i].substr(0, 3) + str[i].substr(str[i].length() - 3);
 }
 cout << productCode[0] << endl;
 cout << productCode[1];
}

• jignatius: Instead of a C-style string array you could use a std::vector (can add or delete this) or std::array (fixed size). That's more C++ style.
• N0way1998: i think array (fixed size) won't work as later on i will make that user will be able to input as much photography kit as he would like to and add them to str array so size of array will change i have never used vector before and im still trying to learn something about but thank you i will keep it in mind and will try to find out more about vector
• jignatius: Then std::vector<std::string> is what you want. Glad I was able to help.