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Required fields*
x * x == 0instead of justx == 0? Forxsuch thatx * x == 0, I would expectsin(q)andsinh(q)to returnqbecause the actual value of sinqand sinhqis so close toqthatqis the closest representable value. Then bothsin (q) / qandsinh (q) / qproduce 1, as does1 - x / 6(becausexis so small that 1 is the closest representable value to 1 −x/6). So what are you gaining withx * x == 0instead of justx == 0?|x|is small, then there is "not enough" information in the sub-normal mantissa to yield results in the error margin.