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Javascript - Remove array elements if all elements are null

Cosider the following array:

let array = [
 {Product Title: "Milk", Product Variant: "2L", Quantity: "3"},
 {Product Title: "Water", Product Variant: "", Quantity: "3"},
 {Product Title: "Pepsi", Product Variant: "", Quantity: ""},
 {Product Title: "", Product Variant: "", Quantity: ""}
 {Product Title: "", Product Variant: "", Quantity: ""}
]

How do I remove elements from the array, if all the elements have no value?

What I've tried:

let contents = []
for (let i in array) {
 Object.keys(array[i]).forEach((k) => array[i][k] == "" && delete array[i][k])
 contents.push(array[i])
}
console.log(contents)

but this returns:

0: {Product Title: "Milk", Product Variant: "2L", Quantity: "3"},
1: {Product Title: "Water", Quantity: "3"},
2: {Product Title: "Pepsi"},
3: {}
4: {}

While I would want:

0: {Product Title: "Milk", Product Variant: "2L", Quantity: "3"},
1: {Product Title: "Water", Product Variant: "", Quantity: "3"},
2: {Product Title: "Pepsi", Product Variant: "", Quantity: ""}

Answer*

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3
  • You beat me to it again 😁! Always nice to see your answers! 👍 Commented Jan 30, 2022 at 10:06
  • Thank you so much, it works. Really like the one line solution Commented Jan 30, 2022 at 10:07
  • @CarstenMassmann Agreed. Her answers are amazing! She is a developer from GOD. Commented Jan 31, 2022 at 11:05

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