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Why does this function return a different value?

Given a day of the week encoded as 0=Sun, 1=Mon, 2=Tue, ...6=Sat, and a boolean indicating if we are on vacation, return a string of the form "7:00" indicating when the alarm clock should ring.

Weekdays, the alarm should be "7:00" and on the weekend it should be "10:00". Unless we are on vacation -- then on weekdays it should be "10:00" and weekends it should be "off"

def alarm_clock(day, vacation):
 if not vacation and 1<=day<=5:
 return "7:00"
 if not vacation and day==0 or day==6:
 return "10:00"
 if vacation and 1<=day<=5:
 return "10:00"
 if vacation and day==0 or day==6:
 return "off"

Why does alarm_clock(6, False) → '10:00' but alarm_clock(6, True) → '10:00' instead of 'off'?

I know the correct answer but I'm still confused to why my initial logic is off.

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Ok I understand that writing: if not vacation and day==0 or day==6: inadvertently assigns (alarm_clock(6,True)) as '10:00' but why does it also assign (alarm_clock(6,False)) as '10:00' aswell?

user16712533
– user16712533

2021年08月20日 09:32:45 +00:00
Commented Aug 20, 2021 at 9:32
AND is proceeded before OR, check this post for further explanation.

Mig B
– Mig B

2021年08月20日 09:58:43 +00:00
Commented Aug 20, 2021 at 9:58
Without parenthesis, if not vacation and day==0 or day==6: return"10:00" is processed as "False and False or True" but alarm_clock(6, False) → '10:00' . Wouldn't "if vacation and (day==0 or day==6): return 'off' " assign it as "off" ?

user16712533
– user16712533

2021年08月20日 10:16:40 +00:00
Commented Aug 20, 2021 at 10:16

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Why does this function return a different value?

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