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sort array based on other array js

I have 2 lists/arrays:

[Examples]:

let labels = ["John", "Sophie", "Hannah", "Emilia"]
let data = [10, 40, 24, 25]

I want to sort both arrays with the order of data. (Each name corresponds with the value in the other array at the same index). I would use an object like this {name: value} but for my needs, they have to be seperate (at least the result). I have found a solution but i find it isnt very elegant.

[Desired Output Example]:

let data = [40, 25, 24, 10]
let labels = ["Sophie", "Emilia", "Hannah", "John"]

basically the other array has to be sorted with the same pattern that the data array will be sorted (numbers ascending)

Answer*

1. Use `.map()` to merge the arrays into an array of arrays (2D array)
 ````
 [[10, 'John'], [40, 'Sophie'], ...]
 ````
2. Then `.sort()` by each sub-array's first element
 ````
 arrArr[0][0] = 10, arrArr[1][0] = 40
 ````
3. Then use a `for...of` loop to `.push()` each element of each sub-array into a new array.

***Details are commented in demo below***






 let labels = ["John", "Sophie", "Hannah", "Emilia"];

 let data = [10, 40, 24, 25];

 // map() into an array of arrays
 // ex. [[10, 'John'], [40, 'Sophie'],...]
 let twoDArr = data.map((num, idx) => [num, labels[idx]]);

 // sort() by the first element of each sub-array.
 // ex. twoDArr[0][0] = 10, twoDarr[1][0] = 40
 let sorted = twoDArr.sort((a, b) => b[0] - a[0]);

 /* 
 for each sub-array of sorted 2D array 
 push sorted[i][0] into an empty array and
 push sorted[i][1] into another empty array
 */

 let keys = [];
 let vals = [];
 for (let [key, val] of sorted) {
 keys.push(key);
 vals.push(val);
 }

 console.log('data: '+keys);
 console.log('labels: '+vals);

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