Return to Answer

Inside bytes literals you may use 2 methods for specifying individual bytes:

1. direct ASCII character, e. g. b'xyz', or
2. escape sequences (starting with \), e.g. b'\n123円\x56\\'

Of course, you may combine both methods in bytes literals, e. g. b'xy\n\x56abc'

So your b'\x6b\x0a' and b'6b0a' a both the valid bytes strings, but unfortunately different.

(The first one is 2 bytes long while the second represents 4 bytes.)

Inside bytes literals you may use 2 methods for specifying individual bytes:

1. a direct ASCII character, e. g. b'xyz', or
2. an escape sequence (starting with \), e.g. b'\n123円\x56\\'

Of course, you may combine both methods in one bytes literal, e. g. b'xy\n\x56abc'

So your b'\x6b\x0a' and b'6b0a' a both the valid bytes literals - but unfortunately different:

• the 1^st one consists of 2 bytes (represented as escape sequences \x6b and \x0a)
• the 2^nd one consists of 4 bytes (represented as ASCII characters 6, b, 0, and a).