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Timeline for type checking in javascript

Current License: CC BY-SA 2.5

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Nov 12, 2020 at 3:01 comment added user1948585 A functional way of type checking stackoverflow.com/a/64794158/1948585
Nov 22, 2015 at 23:20 comment added RobG This answer should be updated as it's inconsistent with the ECMAScript 2015 Number.isInteger function. It should return false for Infinity, not true.
Feb 17, 2014 at 15:04 comment added yhpark Beware, typeof new Number(foo) is "object"
Jan 24, 2014 at 4:26 comment added Mike Stay You can also check if a number x is a valid array index, i.e. a 32-bit integer with x === (x|0). The binary operator casts to a 32-bit int internally, so if casting to an int and then back to a double leaves the value the same, it's a valid 32-bit int. Anything out of range or the wrong type gets cast to 0.
Nov 2, 2013 at 6:09 comment added jrista One could also use constructor equivalence: foo.constructor === Number. One could then throw in the Math.floor or parseInt check to verify the Number is actually an int. The benefit of this is you are actually checking a concrete type name, rather than a string, however that may not quite carry the weight it does in a strongly typed language.
Jul 9, 2013 at 21:44 comment added Andrei If you're using jQuery, you can use it's $.type() function. Ex. $.type("1") # => "string"
Oct 7, 2012 at 10:09 comment added Quentin @NullUserException — That's what I said.
Oct 7, 2012 at 6:54 comment added NullUserException "it doesn't distinguish between different types of Number" That's because there are no different types of Number. All numeric values in JS are 64-bit floats.
Dec 22, 2010 at 23:41 vote accept sova
Dec 22, 2010 at 23:29 comment added m4tt1mus you can also use isNaN(foo) w3schools.com/jsref/jsref_NaN.asp instead of typeof
Dec 22, 2010 at 23:21 history answered Quentin CC BY-SA 2.5

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