This is very simple. Take a look at str.join
print '.'.join([str(a) for a in deints])
Citation from the docs:
str.join(iterable)
Return a string which is the concatenation of the strings in the iterable iterable. The separator between elements is the string providing this method.
This is very simple. Take a look at str.join
print '.'.join([str(a) for a in deints])
Citation from the docs:
str.join(iterable)
Return a string which is the concatenation of the strings in the iterable iterable. The separator between elements is the string providing this method.
This is very simple. Take a look at str.join
print '.'.join([str(a) for a in deints])
Citation from the docs:
str.join(iterable)
Return a string which is the concatenation of the strings in the iterable iterable. The separator between elements is the string providing this method.
This is very simple. Take a look at str.join
print '.'.join([str(a) for a in deints])
Citation from the docs:
str.join(iterable)
Return a string which is the concatenation of the strings in the iterable iterableiterable. The separator between elements is the string providing this method.
This is very simple. Take a look at str.join
print '.'.join([str(a) for a in deints])
Citation from the docs:
str.join(iterable)
Return a string which is the concatenation of the strings in the iterable iterable. The separator between elements is the string providing this method.
This is very simple. Take a look at str.join
print '.'.join([str(a) for a in deints])
Citation from the docs:
str.join(iterable)
Return a string which is the concatenation of the strings in the iterableiterable. The separator between elements is the string providing this method.
This is very simple:. Take a look at str.join
print '.'.join(deints[str(a) for a in deints])
Citation from the docs:
str.join(iterable)
Return a string which is the concatenation of the strings in the iterable iterable. The separator between elements is the string providing this method.
This is very simple:
print '.'.join(deints)
This is very simple. Take a look at str.join
print '.'.join([str(a) for a in deints])
Citation from the docs:
str.join(iterable)
Return a string which is the concatenation of the strings in the iterable iterable. The separator between elements is the string providing this method.