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You should read this.

By putting the files at the same level, you put them is the same package level. In your case, you need to get this architecture:

mypackage
├── __init__.py
├── one.py # contains "import two"
└── two
 ├── __init__.py
 ├── three
 │  ├── __init__.py
 │  └── three.py
 └── two.py # contains "import three"

And then, you can access the package with:

import mypackage.one
import mypackage.one.two
import mypackage.one.two.three

You should read this.

By putting the files at the same level, you put them is the same package level. In your case, you need to get this architecture:

mypackage
├── __init__.py
├── one.py # contains "import two"
└── two
 ├── __init__.py
 ├── two.py # contains "import three"
 └── three
  ├── __init__.py
  └── three.py

And then, you can access the package with:

import mypackage.one
import mypackage.one.two
import mypackage.one.two.three

You should read this.

By put the files at the same level, you put them is the same package level. In your case, you need to get this architecture:

mypackage
├── __init__.py
├── one.py # contains "import two"
└── two
 ├── __init__.py
 ├── three
 │  ├── __init__.py
 │  └── three.py
 └── two.py # contains "import three"

And then, you can access the package with:

import mypackage.one
import mypackage.one.two
import mypackage.one.two.three

You should read this.

By putting the files at the same level, you put them is the same package level. In your case, you need to get this architecture:

mypackage
├── __init__.py
├── one.py # contains "import two"
└── two
 ├── __init__.py
 ├── three
 │  ├── __init__.py
 │  └── three.py
 └── two.py # contains "import three"

And then, you can access the package with:

import mypackage.one
import mypackage.one.two
import mypackage.one.two.three