Timeline for Best way to convert string to array of object in javascript?
Current License: CC BY-SA 2.5
14 events
| when toggle format | what | by | license | comment | |
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| Mar 27, 2014 at 15:43 | vote | accept | Zeck | ||
| Jun 6, 2012 at 4:48 | history | edited | Community Bot | CC BY-SA 3.0 |
http://www.json.org/json2.js was remapped to https://github.com/douglascrockford/JSON-js/blob/master/json2.js by Jarrod Dixon (3)
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| Sep 3, 2010 at 9:47 | history | bounty awarded | Community Bot | ||
| Sep 2, 2010 at 15:52 | history | edited | Steven Sudit | CC BY-SA 2.5 |
deleted 1 characters in body
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| Sep 2, 2010 at 10:50 | history | edited | alcuadrado | CC BY-SA 2.5 |
Expan json2.js explanation
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| Sep 1, 2010 at 23:07 | history | edited | alcuadrado | CC BY-SA 2.5 |
fix error
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| Aug 31, 2010 at 20:41 | comment | added | Russ Cam | Note that json2 still uses eval, but performs some checks to mitigate potential vulnerabilities | |
| Aug 31, 2010 at 16:05 | comment | added | alcuadrado | eval() parses a string as JavaScript source, and as all valid JSON is also valid JavaScript (and it comes from JavaScript Object Notation), you can use eval() to transform it to it's JavaScript representation. It's a common practice to add parents at the beginning and end of the string for security reasons, although using eval() stills pretty insecure. So, var myObject = eval( "(" + myString + ")" ); is just parsing the myString JSON and getting it's value in myObject variable (probably an object or array) | |
| Aug 31, 2010 at 15:33 | comment | added | MEM | What does var myObject = eval( "(" + myString + ")" ); mean? Thanks a lot. | |
| Aug 27, 2010 at 18:35 | history | edited | alcuadrado | CC BY-SA 2.5 |
correct something about keys quoting
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| Aug 27, 2010 at 9:59 | history | edited | alcuadrado | CC BY-SA 2.5 |
added 189 characters in body
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| Aug 27, 2010 at 9:53 | history | edited | alcuadrado | CC BY-SA 2.5 |
added 298 characters in body
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| Aug 27, 2010 at 9:46 | history | edited | alcuadrado | CC BY-SA 2.5 |
got the safari version
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| Aug 27, 2010 at 9:40 | history | answered | alcuadrado | CC BY-SA 2.5 |