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It depends on what you have inside your first() and second() functions.. if you have some async calls, first() may end after second().

For example

function first(){
 console.log("I'm first"); 
}
function second(){
 console.log("I'm second"); 
}
first();
second();

will print

I'm first

I'm second

Now suppose you have an ajax call in your first() function that takes 10 seconds to end:

function first(){
 $.ajax({
 //--- blah blah
 success: function(){
 //--- success runs after 10 seconds
 console.log("I'm first"); 
 }
 })
}

if you run

first();
second();

you will have printed

I'm second

I'm first

Here you can find another example

It depends on what you have inside your first() and second() functions.. if you have some async calls, first() may end after second().

For example

function first(){
 console.log("I'm first"); 
}
function second(){
 console.log("I'm second"); 
}
first();
second();

will print

I'm first

I'm second

Now suppose you have an ajax call in your first() function that takes 10 seconds to end:

function first(){
 $.ajax({
 //--- blah blah
 success: function(){
 //--- success runs after 10 seconds
 console.log("I'm first"); 
 }
 })
}

if you run

first();
second();

you will have printed

I'm second

I'm first

Here you can find another example

It depends on what you have inside your first() and second() functions.. if you have some async calls, first() may end after second().

For example

function first(){
 console.log("I'm first"); 
}
function second(){
 console.log("I'm second"); 
}
first();
second();

will print

I'm first

I'm second

Now suppose you have an ajax call in your first() function that takes 10 seconds to end:

function first(){
 $.ajax({
 //--- blah blah
 success: function(){
 //--- success runs after 10 seconds
 console.log("I'm first"); 
 }
 })
}

if you run

first();
second();

you will have printed

I'm second

I'm first

Here you can another example

It depends on what you have inside your first() and second() functions.. if you have some async calls, first() may end after second().

For example

function first(){
 console.log("I'm first"); 
}
function second(){
 console.log("I'm second"); 
}
first();
second();

will print

I'm first

I'm second

Now suppose you have an ajax call in your first() function that takes 10 seconds to end:

function first(){
 $.ajax({
 //--- blah blah
 success: function(){
 //--- success runs after 10 seconds
 console.log("I'm first"); 
 }
 })
}

if you run

first();
second();

you will have printed

I'm second

I'm first

Here you can find another example

It depends on what you have inside your first() and second() functions.. if you have some async calls, first() may end after second().

For example

function first(){
 console.log("I'm first"); 
}
function second(){
 console.log("I'm second"); 
}
first();
second();

will print

I'm first

I'm second

Now suppose you have an ajax call in your first() function that takes 10 seconds to end:

function first(){
 $.ajax({
 //--- blah blah
 success: function(){
 //--- success runs after 10 seconds
 console.log("I'm first"); 
 }
 })
}

if you run

first();
second();

you will have printed

I'm second

I'm first

It depends on what you have inside your first() and second() functions.. if you have some async calls, first() may end after second().

For example

function first(){
 console.log("I'm first"); 
}
function second(){
 console.log("I'm second"); 
}
first();
second();

will print

I'm first

I'm second

Now suppose you have an ajax call in your first() function that takes 10 seconds to end:

function first(){
 $.ajax({
 //--- blah blah
 success: function(){
 //--- success runs after 10 seconds
 console.log("I'm first"); 
 }
 })
}

if you run

first();
second();

you will have printed

I'm second

I'm first

Here you can another example