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Use json_decode() - But make sure the JSON string is valid, else it'd return NULL. The JSON string you have in the question is not valid (as you can verify with an online validator such as jsonlint.com)

Amal
– Amal

2014年02月18日 11:48:57 +00:00
Commented Feb 18, 2014 at 11:48
If I just search then the appropriate PHP documentation is the first hit.

Quentin
– Quentin

2014年02月18日 11:49:22 +00:00
Commented Feb 18, 2014 at 11:49
sorry I checked with jsonlint.com for my json and it says valid [ { "datetime": "17/02/2014 13:18:30", "type": "testtype", "locationid": "1", "GPSType": "GOOGLE", "GPSLatitude": "1.1", "GPSLongtitude": "1.2", "userid": "admin", "brand": "1234567", "numbers": [ "num1", "num2", "num3" ] } ]

user3323251
– user3323251

2014年02月18日 11:51:39 +00:00
Commented Feb 18, 2014 at 11:51
1

@user3323251 — There is a " in that comment that isn't in the question.

Quentin
– Quentin

2014年02月18日 11:52:15 +00:00
Commented Feb 18, 2014 at 11:52

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