Timeline for nested looping in python
Current License: CC BY-SA 2.5
14 events
| when toggle format | what | by | license | comment | |
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| Dec 15, 2009 at 14:10 | comment | added | Johannes Charra | So bascially you're looking for an algorithm that yields 1. the 1 possibility to omit no commas in your array 2. the 4 possibilities to omit one comma 3. the 6 possibilities to omit two commas 4. the 4 possibilities to omit three commas 5. the 1 possibility to omit four commas ? | |
| Dec 15, 2009 at 14:04 | vote | accept | Hick | ||
| Dec 15, 2009 at 13:47 | history | edited | SilentGhost |
edited tags
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| Dec 15, 2009 at 13:47 | comment | added | SilentGhost | @mekaspersky: that's not what you posted. | |
| Dec 15, 2009 at 13:46 | answer | added | jsbueno | timeline score: 1 | |
| Dec 15, 2009 at 13:46 | answer | added | Michal Čihař | timeline score: 1 | |
| Dec 15, 2009 at 13:43 | comment | added | Hick | in 2nd , 12 is an integer , in 3rd , 23 is an integer . | |
| Dec 15, 2009 at 13:43 | answer | added | Mike D. | timeline score: 2 | |
| Dec 15, 2009 at 13:42 | comment | added | unwind | So if you know the logic, perhaps you should try describing it in words, as a complement to the example output. | |
| Dec 15, 2009 at 13:41 | history | rollback | falstro |
Rollback to Revision 2
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| Dec 15, 2009 at 13:41 | comment | added | SilentGhost | what's the difference between 2nd and 3rd? | |
| Dec 15, 2009 at 13:41 | history | edited | falstro | CC BY-SA 2.5 |
a little style.
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| Dec 15, 2009 at 13:40 | history | edited | unwind | CC BY-SA 2.5 |
Tried to make it readable and sensible at the same time ... challenging!
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| Dec 15, 2009 at 13:36 | history | asked | Hick | CC BY-SA 2.5 |