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Consider the following snippet,

#include<iostream>
#include<stdlib.h>
int main(void)
{
int a[] = {1,2};
a =new int[2];
delete(a);
return 0;
}

This gives an error error: incompatible types in assignment of ‘int*’ to ‘int [2]’. I am statically creating an array of int . a is a pointer(it is of type int[2]) but it can't be used to point to other dynamically allocated arrays because they return pointer of type int*.

If you want to create an array dynamically you have to assign its address to a float*

float * a = new float[10] ;

Refer this too.

Consider the following snippet,

#include<iostream>
#include<stdlib.h>
int main(void)
{
int a[] = {1,2};
a =new int[2];
delete(a);
return 0;
}

This gives an error error: incompatible types in assignment of ‘int*’ to ‘int [2]’. I am statically creating an array of int . a is a pointer(it is of type int[2]) but it can't be used to point to other dynamically allocated arrays because they return pointer of type int*.

If you want to create an array dynamically you have to assign its address to a float*

float * a = new float[10] ;

Refer this too.

float myIDs[] = {
 //Variables
}; 

This declares an array of floats. The array name(is like a const pointer) is associated with only this memory location and can't be used to point to other arrays.

You can use float* arrayName = new float[10]; etc to point to float arrays

Consider the following snippet,

#include<iostream>
#include<stdlib.h>
int main(void)
{
int a[] = {1,2};

a =new int[2];
delete(a);
return 0;
}

This gives an error error: incompatible types in assignment of ‘int*’ to ‘int [2]’. I am statically creating an array of int . a is a pointer(it is of type int[2]) but it can't be used to point to other dynamically allocated arrays because they return pointer of type int*.

If you want to create an array dynamically you have to assign its address to a float*

float * a = new float[10] ;

Refer this too.