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Required fields*

Required fields*

structure initialization

The output of the code has to be zero, but I am having an error, please guide. I can initialize the structure with its type variable but how can I do with the pointer to initialize the whole structure?

#include<stdio.h>
typedef struct student
{
 int roll_id[10];
 int name_id[10];
 int postn;
} student;
int main()
{
 student p; /// here i can do student p={ {0} };
 student *pptr=&p;
 pptr= { {0} }; /// but can i initialize in this way ?? //error: expected 
 expression before ‘{’ token
 pptr->roll_id[9]=1;
 printf (" %d\n", pptr->postn); 
 return 0;
}

Answer*

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  • 1
    I believe you're trying to assign a string literal as an element of an int array. Commented Jan 8, 2013 at 11:13
  • @unwind: pptr->roll_id[0-9]=0; // can i do this without loop Commented Jan 8, 2013 at 11:16
  • 1
    This is wrong! There are no character strings in the question, and braced-enclosed initializer lists are not for assignment. Commented Jan 8, 2013 at 11:37
  • @MikeKwan Thanks, must have mis-read the OP's code in some way. Commented Jan 9, 2013 at 13:22
  • @acraig5075 Fixed the string mis-match, must have been confused yesterday. But yes, compound literals ("brace-enclosed initializer lists") are fine from C99, as I say. Commented Jan 9, 2013 at 13:23

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