Hi all, Is there any way to annotate a plot with icons? The only way to include an image that I've found is using imshow, but imshow does not accept (x,y) coordinates. There probably is an easy solution, but I have not been able to find any. Please be patient :-) Thank you in advance for your reply, Bas van Leeuwen PS, I'm sorry if this mail arrives multiple times, I didn't see the previous one in the archive.
The location of the image can be set by specifying the "extent" keyword, however, this is set in data coordinate. figimage may be close to what you want. http://matplotlib.sourceforge.net/api/pyplot_api.html#matplotlib.pyplot.figimage As far as I know, there is no direct support in matplotlib to place an image with arbitrary transformation. But it may not be difficult to implement. However, "annotate a plot with icons" is not enough to figure out what you really want. Maybe some screenshots from other plotting tool will be helpful. Or, please elaborate how you want to position your image. -JJ On Thu, Jul 30, 2009 at 12:11 PM, Bas van Leeuwen<le...@gm...> wrote: > Hi all, > > Is there any way to annotate a plot with icons? > The only way to include an image that I've found is using imshow, but > imshow does not accept (x,y) coordinates. > > There probably is an easy solution, but I have not been able to find > any. Please be patient :-) > > Thank you in advance for your reply, > Bas van Leeuwen > > PS, I'm sorry if this mail arrives multiple times, I didn't see the > previous one in the archive. > > ------------------------------------------------------------------------------ > Let Crystal Reports handle the reporting - Free Crystal Reports 2008 30-Day > trial. Simplify your report design, integration and deployment - and focus on > what you do best, core application coding. Discover what's new with > Crystal Reports now. http://p.sf.net/sfu/bobj-july > _______________________________________________ > Matplotlib-users mailing list > Mat...@li... > https://lists.sourceforge.net/lists/listinfo/matplotlib-users >
Hi JJ, Thank you for your kind and speedy reply, I completely glanced over the extent parameter. Datacoords are actually what I need so this is perfect for me. To clarify what I want, I want to mark certain parts of a graph with an icon representing the reason it's interesting. Icons are for peaks, trends, correlation, etc. Thank you very much! Bas 2009年7月30日 Jae-Joon Lee <lee...@gm...>: > The location of the image can be set by specifying the "extent" > keyword, however, this is set in data coordinate. > figimage may be close to what you want. > > http://matplotlib.sourceforge.net/api/pyplot_api.html#matplotlib.pyplot.figimage > > As far as I know, there is no direct support in matplotlib to place an > image with arbitrary transformation. But it may not be difficult to > implement. However, "annotate a plot with icons" is not enough to > figure out what you really want. > Maybe some screenshots from other plotting tool will be helpful. Or, > please elaborate how you want to position your image. > > -JJ > > > On Thu, Jul 30, 2009 at 12:11 PM, Bas van Leeuwen<le...@gm...> wrote: >> Hi all, >> >> Is there any way to annotate a plot with icons? >> The only way to include an image that I've found is using imshow, but >> imshow does not accept (x,y) coordinates. >> >> There probably is an easy solution, but I have not been able to find >> any. Please be patient :-) >> >> Thank you in advance for your reply, >> Bas van Leeuwen >> >> PS, I'm sorry if this mail arrives multiple times, I didn't see the >> previous one in the archive. >> >> ------------------------------------------------------------------------------ >> Let Crystal Reports handle the reporting - Free Crystal Reports 2008 30-Day >> trial. Simplify your report design, integration and deployment - and focus on >> what you do best, core application coding. Discover what's new with >> Crystal Reports now. http://p.sf.net/sfu/bobj-july >> _______________________________________________ >> Matplotlib-users mailing list >> Mat...@li... >> https://lists.sourceforge.net/lists/listinfo/matplotlib-users >> >
Hello,
I tried to implement a solution for this issue. Basically I want to
give the x and y position in datacoords and the width + height in
pixels.
However, when using the following code:
im = Image.open("../Icons/Program Icon.png")
limx = self.mainAxes.get_xlim()
limy = self.mainAxes.get_ylim()
[x0, y0], [x1, y1] = self.mainAxes.bbox.get_points()
datawidth = limx[1] - limx[0]
dataheight = limy[1] - limy[0]
pixelwidth = x1 - x0
pixelheight = y1 - y0
adaptedwidth = im.size[0] * (datawidth/pixelwidth)
adaptedheight = im.size[1] * (dataheight/pixelheight)
for peak in Blocks.peaks(self.quote.Close,
self.peakSpanSlider.value()):
self.mainAxes.imshow(im, origin = 'lower', extent =
(date2num(peak.datetime), date2num(peak.datetime) + 100 , 400, 425)) #
left right bottom top
self.mainAxes.set_xlim(limx)
self.mainAxes.set_ylim(limy)
There is no visible result. When zooming in to a place where an image
should be present I encounter the following error every time I move
the mouse.
Traceback (most recent call last):
File "C:\Python25\lib\site-packages\matplotlib\backends\backend_qt4.py",
line 135, in mouseReleaseEvent
FigureCanvasBase.button_release_event( self, x, y, button )
File "C:\Python25\lib\site-packages\matplotlib\backend_bases.py",
line 1198, in button_release_event
self.callbacks.process(s, event)
File "C:\Python25\lib\site-packages\matplotlib\cbook.py", line 155, in process
func(*args, **kwargs)
File "C:\Python25\lib\site-packages\matplotlib\backend_bases.py",
line 2048, in release_zoom
self.draw()
File "C:\Python25\lib\site-packages\matplotlib\backend_bases.py",
line 2070, in draw
self.canvas.draw()
File "C:\Python25\lib\site-packages\matplotlib\backends\backend_qt4agg.py",
line 133, in draw
FigureCanvasAgg.draw(self)
File "C:\Python25\lib\site-packages\matplotlib\backends\backend_agg.py",
line 279, in draw
self.figure.draw(self.renderer)
File "C:\Python25\lib\site-packages\matplotlib\figure.py", line 772, in draw
for a in self.axes: a.draw(renderer)
File "C:\Python25\lib\site-packages\matplotlib\axes.py", line 1545, in draw
im.draw(renderer)
File "C:\Python25\lib\site-packages\matplotlib\image.py", line 233, in draw
im = self.make_image(renderer.get_image_magnification())
File "C:\Python25\lib\site-packages\matplotlib\image.py", line 220,
in make_image
rx = widthDisplay / numcols
ZeroDivisionError: float division
Any idea what might cause this issue? Did I do something wrong? I know
it's not pretty, but it should work right?
Cheers!
Bas
2009年7月30日 Bas van Leeuwen <le...@gm...>:
> Hi JJ,
>
> Thank you for your kind and speedy reply, I completely glanced over
> the extent parameter.
> Datacoords are actually what I need so this is perfect for me.
>
> To clarify what I want, I want to mark certain parts of a graph with
> an icon representing the reason it's interesting. Icons are for peaks,
> trends, correlation, etc.
>
> Thank you very much!
>
> Bas
>
>
> 2009年7月30日 Jae-Joon Lee <lee...@gm...>:
>> The location of the image can be set by specifying the "extent"
>> keyword, however, this is set in data coordinate.
>> figimage may be close to what you want.
>>
>> http://matplotlib.sourceforge.net/api/pyplot_api.html#matplotlib.pyplot.figimage
>>
>> As far as I know, there is no direct support in matplotlib to place an
>> image with arbitrary transformation. But it may not be difficult to
>> implement. However, "annotate a plot with icons" is not enough to
>> figure out what you really want.
>> Maybe some screenshots from other plotting tool will be helpful. Or,
>> please elaborate how you want to position your image.
>>
>> -JJ
>>
>>
>> On Thu, Jul 30, 2009 at 12:11 PM, Bas van Leeuwen<le...@gm...> wrote:
>>> Hi all,
>>>
>>> Is there any way to annotate a plot with icons?
>>> The only way to include an image that I've found is using imshow, but
>>> imshow does not accept (x,y) coordinates.
>>>
>>> There probably is an easy solution, but I have not been able to find
>>> any. Please be patient :-)
>>>
>>> Thank you in advance for your reply,
>>> Bas van Leeuwen
>>>
>>> PS, I'm sorry if this mail arrives multiple times, I didn't see the
>>> previous one in the archive.
>>>
>>> ------------------------------------------------------------------------------
>>> Let Crystal Reports handle the reporting - Free Crystal Reports 2008 30-Day
>>> trial. Simplify your report design, integration and deployment - and focus on
>>> what you do best, core application coding. Discover what's new with
>>> Crystal Reports now. http://p.sf.net/sfu/bobj-july
>>> _______________________________________________
>>> Matplotlib-users mailing list
>>> Mat...@li...
>>> https://lists.sourceforge.net/lists/listinfo/matplotlib-users
>>>
>>
>
A snippet of code does not help in general.
Please take your time to create a simple, standalone code that
reproduces your problem and post that code in this mailing list so
that we can easily test.
Here is the code, based on yours, that works for me.
im = Image.open("icon.jpg")
ax = gca()
limx = ax.get_xlim()
limy = ax.get_ylim()
ax.set_autoscale_on(False)
[x0, y0], [x1, y1] = ax.bbox.get_points()
datawidth = limx[1] - limx[0]
dataheight = limy[1] - limy[0]
pixelwidth = x1 - x0
pixelheight = y1 - y0
adaptedwidth = im.size[0] * (datawidth/pixelwidth)
adaptedheight = im.size[1] * (dataheight/pixelheight)
ax.imshow(im, origin="lower",
extent=(0.5, 0.5+adaptedwidth, 0.5, 0.5+adaptedheight))
plt.draw()
-JJ
On Fri, Jul 31, 2009 at 3:44 PM, Bas van Leeuwen<le...@gm...> wrote:
> Hello,
>
> I tried to implement a solution for this issue. Basically I want to
> give the x and y position in datacoords and the width + height in
> pixels.
> However, when using the following code:
>
> im = Image.open("../Icons/Program Icon.png")
>
> limx = self.mainAxes.get_xlim()
> limy = self.mainAxes.get_ylim()
>
> [x0, y0], [x1, y1] = self.mainAxes.bbox.get_points()
>
> datawidth = limx[1] - limx[0]
> dataheight = limy[1] - limy[0]
> pixelwidth = x1 - x0
> pixelheight = y1 - y0
> adaptedwidth = im.size[0] * (datawidth/pixelwidth)
> adaptedheight = im.size[1] * (dataheight/pixelheight)
>
>
> for peak in Blocks.peaks(self.quote.Close,
> self.peakSpanSlider.value()):
> self.mainAxes.imshow(im, origin = 'lower', extent =
> (date2num(peak.datetime), date2num(peak.datetime) + 100 , 400, 425)) #
> left right bottom top
> self.mainAxes.set_xlim(limx)
> self.mainAxes.set_ylim(limy)
>
> There is no visible result. When zooming in to a place where an image
> should be present I encounter the following error every time I move
> the mouse.
>
> Traceback (most recent call last):
> File "C:\Python25\lib\site-packages\matplotlib\backends\backend_qt4.py",
> line 135, in mouseReleaseEvent
> FigureCanvasBase.button_release_event( self, x, y, button )
> File "C:\Python25\lib\site-packages\matplotlib\backend_bases.py",
> line 1198, in button_release_event
> self.callbacks.process(s, event)
> File "C:\Python25\lib\site-packages\matplotlib\cbook.py", line 155, in process
> func(*args, **kwargs)
> File "C:\Python25\lib\site-packages\matplotlib\backend_bases.py",
> line 2048, in release_zoom
> self.draw()
> File "C:\Python25\lib\site-packages\matplotlib\backend_bases.py",
> line 2070, in draw
> self.canvas.draw()
> File "C:\Python25\lib\site-packages\matplotlib\backends\backend_qt4agg.py",
> line 133, in draw
> FigureCanvasAgg.draw(self)
> File "C:\Python25\lib\site-packages\matplotlib\backends\backend_agg.py",
> line 279, in draw
> self.figure.draw(self.renderer)
> File "C:\Python25\lib\site-packages\matplotlib\figure.py", line 772, in draw
> for a in self.axes: a.draw(renderer)
> File "C:\Python25\lib\site-packages\matplotlib\axes.py", line 1545, in draw
> im.draw(renderer)
> File "C:\Python25\lib\site-packages\matplotlib\image.py", line 233, in draw
> im = self.make_image(renderer.get_image_magnification())
> File "C:\Python25\lib\site-packages\matplotlib\image.py", line 220,
> in make_image
> rx = widthDisplay / numcols
> ZeroDivisionError: float division
>
> Any idea what might cause this issue? Did I do something wrong? I know
> it's not pretty, but it should work right?
>
> Cheers!
> Bas
>
>
>
> 2009年7月30日 Bas van Leeuwen <le...@gm...>:
>> Hi JJ,
>>
>> Thank you for your kind and speedy reply, I completely glanced over
>> the extent parameter.
>> Datacoords are actually what I need so this is perfect for me.
>>
>> To clarify what I want, I want to mark certain parts of a graph with
>> an icon representing the reason it's interesting. Icons are for peaks,
>> trends, correlation, etc.
>>
>> Thank you very much!
>>
>> Bas
>>
>>
>> 2009年7月30日 Jae-Joon Lee <lee...@gm...>:
>>> The location of the image can be set by specifying the "extent"
>>> keyword, however, this is set in data coordinate.
>>> figimage may be close to what you want.
>>>
>>> http://matplotlib.sourceforge.net/api/pyplot_api.html#matplotlib.pyplot.figimage
>>>
>>> As far as I know, there is no direct support in matplotlib to place an
>>> image with arbitrary transformation. But it may not be difficult to
>>> implement. However, "annotate a plot with icons" is not enough to
>>> figure out what you really want.
>>> Maybe some screenshots from other plotting tool will be helpful. Or,
>>> please elaborate how you want to position your image.
>>>
>>> -JJ
>>>
>>>
>>> On Thu, Jul 30, 2009 at 12:11 PM, Bas van Leeuwen<le...@gm...> wrote:
>>>> Hi all,
>>>>
>>>> Is there any way to annotate a plot with icons?
>>>> The only way to include an image that I've found is using imshow, but
>>>> imshow does not accept (x,y) coordinates.
>>>>
>>>> There probably is an easy solution, but I have not been able to find
>>>> any. Please be patient :-)
>>>>
>>>> Thank you in advance for your reply,
>>>> Bas van Leeuwen
>>>>
>>>> PS, I'm sorry if this mail arrives multiple times, I didn't see the
>>>> previous one in the archive.
>>>>
>>>> ------------------------------------------------------------------------------
>>>> Let Crystal Reports handle the reporting - Free Crystal Reports 2008 30-Day
>>>> trial. Simplify your report design, integration and deployment - and focus on
>>>> what you do best, core application coding. Discover what's new with
>>>> Crystal Reports now. http://p.sf.net/sfu/bobj-july
>>>> _______________________________________________
>>>> Matplotlib-users mailing list
>>>> Mat...@li...
>>>> https://lists.sourceforge.net/lists/listinfo/matplotlib-users
>>>>
>>>
>>
>
> ------------------------------------------------------------------------------
> Let Crystal Reports handle the reporting - Free Crystal Reports 2008 30-Day
> trial. Simplify your report design, integration and deployment - and focus on
> what you do best, core application coding. Discover what's new with
> Crystal Reports now. http://p.sf.net/sfu/bobj-july
> _______________________________________________
> Matplotlib-users mailing list
> Mat...@li...
> https://lists.sourceforge.net/lists/listinfo/matplotlib-users
>
On Sun, Aug 2, 2009 at 1:28 PM, Jae-Joon Lee<lee...@gm...> wrote: > A snippet of code does not help in general. > Please take your time to create a simple, standalone code that > reproduces your problem and post that code in this mailing list so > that we can easily test. > > Here is the code, based on yours, that works for me. The other approach is to use a figimage and use the ax.transData instance to convert data coords to fig coords for the offsets. JDH
Hi,
Sorry about the snippet, I will privide working code from now on.
I found a reproduction path for the error, it occurs (seemingly
random, but frequent) when there is more than one image in the plot
and you try to zoom. Code:
import Image
from pylab import *
im = Image.open("icon.png")
ax = subplot(111)
limx = ax.set_xlim((-5, 15))
limy = ax.set_ylim((-5, 15))
ax.set_autoscale_on(False)
[x0, y0], [x1, y1] = ax.bbox.get_points()
datawidth = limx[1] - limx[0]
dataheight = limy[1] - limy[0]
pixelwidth = x1 - x0
pixelheight = y1 - y0
adaptedwidth = im.size[0] * (datawidth / pixelwidth)
adaptedheight = im.size[1] * (dataheight / pixelheight)
for i in range(0,10,2):
ax.imshow(im, origin="lower",
extent=(i, i + adaptedwidth, i, i + adaptedheight))
plt.draw()
show()
Thank you very much for the support!
Bas
PS, @John, I'd like to try the imshow approach first because it is not
in a figure but in a QT frame containing several subplots. But thank
youfor the suggestion, I will try if the imshow approach appears
fruitless.
2009年8月2日 Jae-Joon Lee <lee...@gm...>:
> A snippet of code does not help in general.
> Please take your time to create a simple, standalone code that
> reproduces your problem and post that code in this mailing list so
> that we can easily test.
>
> Here is the code, based on yours, that works for me.
>
> im = Image.open("icon.jpg")
>
> ax = gca()
> limx = ax.get_xlim()
> limy = ax.get_ylim()
> ax.set_autoscale_on(False)
>
> [x0, y0], [x1, y1] = ax.bbox.get_points()
>
> datawidth = limx[1] - limx[0]
> dataheight = limy[1] - limy[0]
> pixelwidth = x1 - x0
> pixelheight = y1 - y0
> adaptedwidth = im.size[0] * (datawidth/pixelwidth)
> adaptedheight = im.size[1] * (dataheight/pixelheight)
>
> ax.imshow(im, origin="lower",
> extent=(0.5, 0.5+adaptedwidth, 0.5, 0.5+adaptedheight))
>
>
> plt.draw()
>
> -JJ
>
>
>
> On Fri, Jul 31, 2009 at 3:44 PM, Bas van Leeuwen<le...@gm...> wrote:
>> Hello,
>>
>> I tried to implement a solution for this issue. Basically I want to
>> give the x and y position in datacoords and the width + height in
>> pixels.
>> However, when using the following code:
>>
>> im = Image.open("../Icons/Program Icon.png")
>>
>> limx = self.mainAxes.get_xlim()
>> limy = self.mainAxes.get_ylim()
>>
>> [x0, y0], [x1, y1] = self.mainAxes.bbox.get_points()
>>
>> datawidth = limx[1] - limx[0]
>> dataheight = limy[1] - limy[0]
>> pixelwidth = x1 - x0
>> pixelheight = y1 - y0
>> adaptedwidth = im.size[0] * (datawidth/pixelwidth)
>> adaptedheight = im.size[1] * (dataheight/pixelheight)
>>
>>
>> for peak in Blocks.peaks(self.quote.Close,
>> self.peakSpanSlider.value()):
>> self.mainAxes.imshow(im, origin = 'lower', extent =
>> (date2num(peak.datetime), date2num(peak.datetime) + 100 , 400, 425)) #
>> left right bottom top
>> self.mainAxes.set_xlim(limx)
>> self.mainAxes.set_ylim(limy)
>>
>> There is no visible result. When zooming in to a place where an image
>> should be present I encounter the following error every time I move
>> the mouse.
>>
>> Traceback (most recent call last):
>> File "C:\Python25\lib\site-packages\matplotlib\backends\backend_qt4.py",
>> line 135, in mouseReleaseEvent
>> FigureCanvasBase.button_release_event( self, x, y, button )
>> File "C:\Python25\lib\site-packages\matplotlib\backend_bases.py",
>> line 1198, in button_release_event
>> self.callbacks.process(s, event)
>> File "C:\Python25\lib\site-packages\matplotlib\cbook.py", line 155, in process
>> func(*args, **kwargs)
>> File "C:\Python25\lib\site-packages\matplotlib\backend_bases.py",
>> line 2048, in release_zoom
>> self.draw()
>> File "C:\Python25\lib\site-packages\matplotlib\backend_bases.py",
>> line 2070, in draw
>> self.canvas.draw()
>> File "C:\Python25\lib\site-packages\matplotlib\backends\backend_qt4agg.py",
>> line 133, in draw
>> FigureCanvasAgg.draw(self)
>> File "C:\Python25\lib\site-packages\matplotlib\backends\backend_agg.py",
>> line 279, in draw
>> self.figure.draw(self.renderer)
>> File "C:\Python25\lib\site-packages\matplotlib\figure.py", line 772, in draw
>> for a in self.axes: a.draw(renderer)
>> File "C:\Python25\lib\site-packages\matplotlib\axes.py", line 1545, in draw
>> im.draw(renderer)
>> File "C:\Python25\lib\site-packages\matplotlib\image.py", line 233, in draw
>> im = self.make_image(renderer.get_image_magnification())
>> File "C:\Python25\lib\site-packages\matplotlib\image.py", line 220,
>> in make_image
>> rx = widthDisplay / numcols
>> ZeroDivisionError: float division
>>
>> Any idea what might cause this issue? Did I do something wrong? I know
>> it's not pretty, but it should work right?
>>
>> Cheers!
>> Bas
>>
>>
>>
>> 2009年7月30日 Bas van Leeuwen <le...@gm...>:
>>> Hi JJ,
>>>
>>> Thank you for your kind and speedy reply, I completely glanced over
>>> the extent parameter.
>>> Datacoords are actually what I need so this is perfect for me.
>>>
>>> To clarify what I want, I want to mark certain parts of a graph with
>>> an icon representing the reason it's interesting. Icons are for peaks,
>>> trends, correlation, etc.
>>>
>>> Thank you very much!
>>>
>>> Bas
>>>
>>>
>>> 2009年7月30日 Jae-Joon Lee <lee...@gm...>:
>>>> The location of the image can be set by specifying the "extent"
>>>> keyword, however, this is set in data coordinate.
>>>> figimage may be close to what you want.
>>>>
>>>> http://matplotlib.sourceforge.net/api/pyplot_api.html#matplotlib.pyplot.figimage
>>>>
>>>> As far as I know, there is no direct support in matplotlib to place an
>>>> image with arbitrary transformation. But it may not be difficult to
>>>> implement. However, "annotate a plot with icons" is not enough to
>>>> figure out what you really want.
>>>> Maybe some screenshots from other plotting tool will be helpful. Or,
>>>> please elaborate how you want to position your image.
>>>>
>>>> -JJ
>>>>
>>>>
>>>> On Thu, Jul 30, 2009 at 12:11 PM, Bas van Leeuwen<le...@gm...> wrote:
>>>>> Hi all,
>>>>>
>>>>> Is there any way to annotate a plot with icons?
>>>>> The only way to include an image that I've found is using imshow, but
>>>>> imshow does not accept (x,y) coordinates.
>>>>>
>>>>> There probably is an easy solution, but I have not been able to find
>>>>> any. Please be patient :-)
>>>>>
>>>>> Thank you in advance for your reply,
>>>>> Bas van Leeuwen
>>>>>
>>>>> PS, I'm sorry if this mail arrives multiple times, I didn't see the
>>>>> previous one in the archive.
>>>>>
>>>>> ------------------------------------------------------------------------------
>>>>> Let Crystal Reports handle the reporting - Free Crystal Reports 2008 30-Day
>>>>> trial. Simplify your report design, integration and deployment - and focus on
>>>>> what you do best, core application coding. Discover what's new with
>>>>> Crystal Reports now. http://p.sf.net/sfu/bobj-july
>>>>> _______________________________________________
>>>>> Matplotlib-users mailing list
>>>>> Mat...@li...
>>>>> https://lists.sourceforge.net/lists/listinfo/matplotlib-users
>>>>>
>>>>
>>>
>>
>> ------------------------------------------------------------------------------
>> Let Crystal Reports handle the reporting - Free Crystal Reports 2008 30-Day
>> trial. Simplify your report design, integration and deployment - and focus on
>> what you do best, core application coding. Discover what's new with
>> Crystal Reports now. http://p.sf.net/sfu/bobj-july
>> _______________________________________________
>> Matplotlib-users mailing list
>> Mat...@li...
>> https://lists.sourceforge.net/lists/listinfo/matplotlib-users
>>
>
On Mon, Aug 3, 2009 at 6:55 AM, Bas van Leeuwen<le...@gm...> wrote: > PS, @John, I'd like to try the imshow approach first because it is not > in a figure but in a QT frame containing several subplots. But thank > youfor the suggestion, I will try if the imshow approach appears > fruitless. All matplotlib axes and subplots live in figures, you just may not know it. The call to gca in your code below: >> ax = gca() >> limx = ax.get_xlim() automatically creates a figure and adds the axes to is. So you can still access the figure, eg fig = ax.figure You can then call figimage # transform from axes coorrs (x,y) -> display coords (xo,yo) xo, yo = ax.transData.transform_point((x,y)) fig.figimage(Z, xo, yo) where Z is your image array JDH
Hmm, your code runs just fine for me (of course with different icon,
but I don't think it matters).
Can you try to install the 0.99rc version of mpl and see if it solves
the problem?
Since the error is not reproduced in my side, I have little to help.
Also, try the figimage and see if you see a same error.
Regards,
-JJ
On Mon, Aug 3, 2009 at 7:55 AM, Bas van Leeuwen<le...@gm...> wrote:
> Hi,
>
> Sorry about the snippet, I will privide working code from now on.
> I found a reproduction path for the error, it occurs (seemingly
> random, but frequent) when there is more than one image in the plot
> and you try to zoom. Code:
>
> import Image
> from pylab import *
> im = Image.open("icon.png")
>
> ax = subplot(111)
> limx = ax.set_xlim((-5, 15))
> limy = ax.set_ylim((-5, 15))
> ax.set_autoscale_on(False)
>
> [x0, y0], [x1, y1] = ax.bbox.get_points()
>
> datawidth = limx[1] - limx[0]
> dataheight = limy[1] - limy[0]
> pixelwidth = x1 - x0
> pixelheight = y1 - y0
> adaptedwidth = im.size[0] * (datawidth / pixelwidth)
> adaptedheight = im.size[1] * (dataheight / pixelheight)
>
> for i in range(0,10,2):
> ax.imshow(im, origin="lower",
> extent=(i, i + adaptedwidth, i, i + adaptedheight))
>
> plt.draw()
> show()
>
> Thank you very much for the support!
> Bas
>
> PS, @John, I'd like to try the imshow approach first because it is not
> in a figure but in a QT frame containing several subplots. But thank
> youfor the suggestion, I will try if the imshow approach appears
> fruitless.
>
>
> 2009年8月2日 Jae-Joon Lee <lee...@gm...>:
>> A snippet of code does not help in general.
>> Please take your time to create a simple, standalone code that
>> reproduces your problem and post that code in this mailing list so
>> that we can easily test.
>>
>> Here is the code, based on yours, that works for me.
>>
>> im = Image.open("icon.jpg")
>>
>> ax = gca()
>> limx = ax.get_xlim()
>> limy = ax.get_ylim()
>> ax.set_autoscale_on(False)
>>
>> [x0, y0], [x1, y1] = ax.bbox.get_points()
>>
>> datawidth = limx[1] - limx[0]
>> dataheight = limy[1] - limy[0]
>> pixelwidth = x1 - x0
>> pixelheight = y1 - y0
>> adaptedwidth = im.size[0] * (datawidth/pixelwidth)
>> adaptedheight = im.size[1] * (dataheight/pixelheight)
>>
>> ax.imshow(im, origin="lower",
>> extent=(0.5, 0.5+adaptedwidth, 0.5, 0.5+adaptedheight))
>>
>>
>> plt.draw()
>>
>> -JJ
>>
>>
>>
>> On Fri, Jul 31, 2009 at 3:44 PM, Bas van Leeuwen<le...@gm...> wrote:
>>> Hello,
>>>
>>> I tried to implement a solution for this issue. Basically I want to
>>> give the x and y position in datacoords and the width + height in
>>> pixels.
>>> However, when using the following code:
>>>
>>> im = Image.open("../Icons/Program Icon.png")
>>>
>>> limx = self.mainAxes.get_xlim()
>>> limy = self.mainAxes.get_ylim()
>>>
>>> [x0, y0], [x1, y1] = self.mainAxes.bbox.get_points()
>>>
>>> datawidth = limx[1] - limx[0]
>>> dataheight = limy[1] - limy[0]
>>> pixelwidth = x1 - x0
>>> pixelheight = y1 - y0
>>> adaptedwidth = im.size[0] * (datawidth/pixelwidth)
>>> adaptedheight = im.size[1] * (dataheight/pixelheight)
>>>
>>>
>>> for peak in Blocks.peaks(self.quote.Close,
>>> self.peakSpanSlider.value()):
>>> self.mainAxes.imshow(im, origin = 'lower', extent =
>>> (date2num(peak.datetime), date2num(peak.datetime) + 100 , 400, 425)) #
>>> left right bottom top
>>> self.mainAxes.set_xlim(limx)
>>> self.mainAxes.set_ylim(limy)
>>>
>>> There is no visible result. When zooming in to a place where an image
>>> should be present I encounter the following error every time I move
>>> the mouse.
>>>
>>> Traceback (most recent call last):
>>> File "C:\Python25\lib\site-packages\matplotlib\backends\backend_qt4.py",
>>> line 135, in mouseReleaseEvent
>>> FigureCanvasBase.button_release_event( self, x, y, button )
>>> File "C:\Python25\lib\site-packages\matplotlib\backend_bases.py",
>>> line 1198, in button_release_event
>>> self.callbacks.process(s, event)
>>> File "C:\Python25\lib\site-packages\matplotlib\cbook.py", line 155, in process
>>> func(*args, **kwargs)
>>> File "C:\Python25\lib\site-packages\matplotlib\backend_bases.py",
>>> line 2048, in release_zoom
>>> self.draw()
>>> File "C:\Python25\lib\site-packages\matplotlib\backend_bases.py",
>>> line 2070, in draw
>>> self.canvas.draw()
>>> File "C:\Python25\lib\site-packages\matplotlib\backends\backend_qt4agg.py",
>>> line 133, in draw
>>> FigureCanvasAgg.draw(self)
>>> File "C:\Python25\lib\site-packages\matplotlib\backends\backend_agg.py",
>>> line 279, in draw
>>> self.figure.draw(self.renderer)
>>> File "C:\Python25\lib\site-packages\matplotlib\figure.py", line 772, in draw
>>> for a in self.axes: a.draw(renderer)
>>> File "C:\Python25\lib\site-packages\matplotlib\axes.py", line 1545, in draw
>>> im.draw(renderer)
>>> File "C:\Python25\lib\site-packages\matplotlib\image.py", line 233, in draw
>>> im = self.make_image(renderer.get_image_magnification())
>>> File "C:\Python25\lib\site-packages\matplotlib\image.py", line 220,
>>> in make_image
>>> rx = widthDisplay / numcols
>>> ZeroDivisionError: float division
>>>
>>> Any idea what might cause this issue? Did I do something wrong? I know
>>> it's not pretty, but it should work right?
>>>
>>> Cheers!
>>> Bas
>>>
>>>
>>>
>>> 2009年7月30日 Bas van Leeuwen <le...@gm...>:
>>>> Hi JJ,
>>>>
>>>> Thank you for your kind and speedy reply, I completely glanced over
>>>> the extent parameter.
>>>> Datacoords are actually what I need so this is perfect for me.
>>>>
>>>> To clarify what I want, I want to mark certain parts of a graph with
>>>> an icon representing the reason it's interesting. Icons are for peaks,
>>>> trends, correlation, etc.
>>>>
>>>> Thank you very much!
>>>>
>>>> Bas
>>>>
>>>>
>>>> 2009年7月30日 Jae-Joon Lee <lee...@gm...>:
>>>>> The location of the image can be set by specifying the "extent"
>>>>> keyword, however, this is set in data coordinate.
>>>>> figimage may be close to what you want.
>>>>>
>>>>> http://matplotlib.sourceforge.net/api/pyplot_api.html#matplotlib.pyplot.figimage
>>>>>
>>>>> As far as I know, there is no direct support in matplotlib to place an
>>>>> image with arbitrary transformation. But it may not be difficult to
>>>>> implement. However, "annotate a plot with icons" is not enough to
>>>>> figure out what you really want.
>>>>> Maybe some screenshots from other plotting tool will be helpful. Or,
>>>>> please elaborate how you want to position your image.
>>>>>
>>>>> -JJ
>>>>>
>>>>>
>>>>> On Thu, Jul 30, 2009 at 12:11 PM, Bas van Leeuwen<le...@gm...> wrote:
>>>>>> Hi all,
>>>>>>
>>>>>> Is there any way to annotate a plot with icons?
>>>>>> The only way to include an image that I've found is using imshow, but
>>>>>> imshow does not accept (x,y) coordinates.
>>>>>>
>>>>>> There probably is an easy solution, but I have not been able to find
>>>>>> any. Please be patient :-)
>>>>>>
>>>>>> Thank you in advance for your reply,
>>>>>> Bas van Leeuwen
>>>>>>
>>>>>> PS, I'm sorry if this mail arrives multiple times, I didn't see the
>>>>>> previous one in the archive.
>>>>>>
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>>>>>
>>>>
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