That's good to know. I tried googling it, but I guess I should've also
checked CVS as well. I'm sure it's better than my hack anyways -- just
good to have my scripts working again. I tend to prefer the subplot(w,
h, n) since most of my plotting is automated, and it's more of a pain to
have to convert the parameters to a string first, etc.
A
Eric Firing wrote:
> Abe,
>
> That bug has been fixed in CVS; like you, I tripped over it in 0.82
> and tracked it down--but someone else had already fixed it. A
> workaround, if you don't want to install from CVS, is to use the old
> subplot(211) form instead of subplot(2,1,1).
>
> Eric
>
> Abraham Schneider wrote:
>
>> Hi. I just installed the newest version of matplotlib (0.82), and
>> discovered all my subplots were ending on top of each other. After
>> going through my code and verifying everything looked okay, I tried a
>> simple:
>>
>> subplot(2, 1, 1); plot(range(0, 10)); subplot(2, 2, 2); plot(range(0,
>> 10))
>>
>> and still only got one subplot. I went to the matplotlib code, and
>> after some prodding, discovered that all the keys for the _seen map
>> were exactly the same. Going to the _make_key function revealed that
>> my use of subplot (i.e. three seperate arguments), was not working.
>> Here is a fix that seems to work for me:
>>
>> (int _make_key function):
>> if iterable(args[0]):
>> key = tuple(args[0]), tuple( fixitems(kwargs.items()))
>> ## NEW
>> elif len(args) > 1:
>> key = args, tuple( fixitems(kwargs.items()))
>> ## \NEW
>> else:
>> key = args[0], tuple(fixitems( kwargs.items()))
>>
>> Abe
>>
>>
>>
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>
>
>
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