buf.writeUInt32LE(value[, offset])


版本历史
版本变更
v14.9.0, v12.19.0

此函数也可用作 buf.writeUint32LE()

v10.0.0

删除了 noAssert 并且不再隐式强制将偏移量强制转换为 uint32

v0.5.5

新增于: v0.5.5

  • value <integer> 要写入 buf 的数字。

    \value <integer> Number to be written to buf.

  • offset <integer> 开始写入之前要跳过的字节数。必须满足 0 <= offset <= buf.length - 4。默认值:0

    \offset <integer> Number of bytes to skip before starting to write. Must satisfy 0 <= offset <= buf.length - 4. Default: 0.

  • 返回:<integer> offset 加上写入的字节数。

    \Returns: <integer> offset plus the number of bytes written.

value 作为小端序写入 buf 中指定的 offsetvalue 必须是有效的无符号 32 位整数。当 value 不是无符号 32 位整数时,则行为未定义。

\Writes value to buf at the specified offset as little-endian. The value must be a valid unsigned 32-bit integer. Behavior is undefined when value is anything other than an unsigned 32-bit integer.

此函数也可在 writeUint32LE 别名下使用。

\This function is also available under the writeUint32LE alias.

import { Buffer } from 'node:buffer';
const buf = Buffer.allocUnsafe(4);
buf.writeUInt32LE(0xfeedface, 0);
console.log(buf);
// Prints: <Buffer ce fa ed fe>const { Buffer } = require('node:buffer');
const buf = Buffer.allocUnsafe(4);
buf.writeUInt32LE(0xfeedface, 0);
console.log(buf);
// Prints: <Buffer ce fa ed fe>

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