buf.writeUInt32LE(value[, offset])
版本历史
| 版本 | 变更 |
|---|---|
| v14.9.0, v12.19.0 | 此函数也可用作 |
| v10.0.0 | 删除了 |
| v0.5.5 | 新增于: v0.5.5 |
-
value<integer> 要写入buf的数字。\
value<integer> Number to be written tobuf. -
offset<integer> 开始写入之前要跳过的字节数。必须满足0 <= offset <= buf.length - 4。默认值:0。\
offset<integer> Number of bytes to skip before starting to write. Must satisfy0 <= offset <= buf.length - 4. Default:0. -
返回:<integer>
offset加上写入的字节数。\Returns: <integer>
offsetplus the number of bytes written.
将 value 作为小端序写入 buf 中指定的 offset。value 必须是有效的无符号 32 位整数。当 value 不是无符号 32 位整数时,则行为未定义。
\Writes value to buf at the specified offset as little-endian. The value
must be a valid unsigned 32-bit integer. Behavior is undefined when value is
anything other than an unsigned 32-bit integer.
此函数也可在 writeUint32LE 别名下使用。
\This function is also available under the writeUint32LE alias.
import { Buffer } from 'node:buffer'; const buf = Buffer.allocUnsafe(4); buf.writeUInt32LE(0xfeedface, 0); console.log(buf); // Prints: <Buffer ce fa ed fe>const { Buffer } = require('node:buffer'); const buf = Buffer.allocUnsafe(4); buf.writeUInt32LE(0xfeedface, 0); console.log(buf); // Prints: <Buffer ce fa ed fe>