Trihyperboloid
Consider the solid enclosed by the three hyperboloids specified by the inequalities
This work dubs this solid the "trihyperboloid."
The basic shape of the trihyperbolid is that of a stella octangula with a "web" hung across adjacent faces.
The surface area of the trihyperboloid is given by
(OEIS A347903), where R[z] denotes the real part of z. The surface area can be given as a complicated (but likely simplifyable) closed-form expression based on evaluation of the integral
in terms of natural logarithms, dilogarithms, and trigamma functions (E. Weisstein Sep. 15-20, 2021).
Knill (2017) proposed as a challenge to Harvard summer school students that they prove that the volume was equal to ln256=8ln2. The problem was solved by student Runze Li, who gave the solution in terms of the mysterious integral
A more straightforward analysis was given by Villarino and Várilly (2024), who showed that
| V=8(3I+I_1+I_2), |
(11)
|
where I_1=1/6 and I_2=1/3 are the volumes of the two tetrahedra with common face (0,0,1), (0,1,0), and (1,0,0) and apices (0,0,0) and (1,1,1) and
Plugging in the values for I_1, I_2, and I_3 then gives the expected result
| V=ln256=8ln2=5.54517744... |
(14)
|
(OEIS A257872).
See also
Hyperboloid, One-Sheeted Hyperboloid, Steinmetz Solid, Stella OctangulaExplore with Wolfram|Alpha
References
Knill, O. "Archimedes Revenge Solution." https://people.math.harvard.edu/~knill/teaching/summer2017/exhibits/revenge/.Sloane, N. J. A. Sequences A257872 and A347903 in "The On-Line Encyclopedia of Integer Sequences."Villarino, M. B. and Várilly, J. C. "Archimedes' Revenge." College Math. J. 55, 257-259, 2024. https://doi.org/10.1080/07468342.2023.2285686.Referenced on Wolfram|Alpha
TrihyperboloidCite this as:
Weisstein, Eric W. "Trihyperboloid." From MathWorld--A Wolfram Resource. https://mathworld.wolfram.com/Trihyperboloid.html