To check if number is in range(x,y)

Sat Dec 12 11:51:00 EST 2020

On 2020年12月12日 15:12, Bischoop wrote:
> I need to check if input number is 1-5. Whatever I try it's not
> working. Here are my aproaches to the problem: https://bpa.st/H62A
>> What I'm doing wrong and how I should do it?

A range is similar to a list in that it contains just the numbers
listed:
 >>> r = range(10)
 >>> 2 in r
 True
 >>> 2.5 in r
 False
 >>> r = range(1, 10, 2)
 >>> 2 in r
 False
 >>> list(r)
 [1, 3, 5, 7, 9]
It also doesn't automatically convert from the string inputs you're
getting from the input() function:
 >>> s = "5"
 >>> s in r
 False
 >>> int(s) in r
 True
Additionally, note that the endpoint of the range is exclusive so
 >>> r = range(1, 10)
 >>> 10 in r
 False
 >>> list(r)
 [1, 2, 3, 4, 5, 6, 7, 8, 9]
If you want numeric-range checks, Python provides the lovely
double-comparison syntax:
 >>> x = 5
 >>> 2 < x < 10
 True
 >>> x = 5.5
 >>> 2 < x < 10
 True
 >>> s = "5"
 >>> 2 < s < 10
 Traceback…
 >>> 2 < int(s) < 10
 True
Hopefully this gives you the hints that you need to troubleshoot.
-tkc