list of dictionaries search using kwargs

Mon Dec 7 17:53:37 EST 2020

On Mon, Dec 7, 2020 at 5:42 PM Matt Wheeler <m at funkyhat.org> wrote:
>> for item in self.data:
> if all(item[k] == v for k,v in kwargs.items()):
> return item
>> Or
>> return [item for item in self.data if all(item[k] == v for k,v in kwargs.items())]
>> to return all matches
>> Beware though that either of these will be slow if your list of dicts is large.
> If the list is large enough that this becomes slow, consider using a database (e.g. sqlite or other SQL DB) instead.

Thanks! Works perfectly.
> On 7 Dec 2020, 22:06 +0000, Larry Martell <larry.martell at gmail.com>, wrote:
>> I have a class that has an object that contains a list of dicts. I
>> want to have a class method that takes a variable number of key/value
>> pairs and searches the list and returns the item that matches the
>> arguments.
>>> If I know the key value pairs I can do something like this:
>>> instance = next(item for item in data] if\
>> item["appCode"] == 1 and\
>> item["componentCode"] == "DB" and\
>> item["environmentEnumID"] == 12 and\
>> item["serverName"] == 'foo', None)
>>> But in my class method if I have:
>>> def find_data_row(self, **kwargs):
>>> and I call it:
>>> find_data_row(appCode=1, componentCode='DB', ...)
>>> How can I do the search in a pythonic way?
>> --
>> https://mail.python.org/mailman/listinfo/python-list