Regarding Regex timeout behavior to minimize CPU consumption

Sat Dec 5 17:42:11 EST 2020

 Hi,
 Timeout: no idea. But check out re.compile and re.iterfind as they might
 speed things up. I often compile a regex once upon import, then use it in
 functions
 On 27 Nov 2020 13:33, Shahique Khan <shahiquzzama at gmail.com> wrote:
 Hi Team,
 I have noticed if our regex sometimes does not give a result and on that
 time regex took more time in returning response (empty response).
 My Question is can we set a timeout parameter (in seconds/millisecond)
 with
 re.find or anywhere in code to avoid CPU consumption if regex takes more
 time in execution.
 Below is the example, which take more time in execution: (in this case
 can
 we set timeout to kill the execution to avoid CPU consumption)
 regex = r'data-stid="section-room-list"[\s\S]*?>\s*([\s\S]*?)\s*' \

 r'(?:class\s*=\s*"\s*sticky-book-now\s*"|</ul>\s*</section>|id\s*=\s*"Location")'
 rooms_blocks_to_be_replace = re.findall(regex, html_template)
 Please help me, I will be very thankful for this.
 Thanks,
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