List replication operator

Fri May 25 13:13:40 EDT 2018

On 25/05/2018 17:58, Rob Gaddi wrote:
> So, in the spirit of explicit being better than implicit, please assume 
> that for actual implementation replicate would be a static method of 
> actual list, rather than the conveniently executable hackjob below.
>> _list = list
> _nodefault = object()
>> class list(_list):
>   @staticmethod
>   def replicate(*n, fill=_nodefault, call=list):

That seems to work, but the dimensions are created in reverse order to 
what I expected. Which is to have the order of indices corresponding to 
the order of dimensions. So:
 x=list.replicate(2,3,4)
 print (len(x))
 print (len(x[0]))
 print (len(x[0][0]))
Gives output of 4, 3, 2 rather than 2, 3, 4.
Which means that x[0][0][3] is a bounds error.
-- 
bartc