List replication operator

Fri May 25 06:48:49 EDT 2018

Steven D'Aprano <steve+comp.lang.python at pearwood.info> writes:
> On 2018年5月24日 16:05:32 -0700, Paul wrote:
>>> How would one make a multi-dimensional list now, with truly-separate sub
>> lists? Is there just no way to do it with the replication operator?
>> Correct. Let's say you want to make a 1-D list with three items 
> initialised to zero. This works brilliantly:
>> py> [0]*3
> [0, 0, 0]
>> This seems like it ought to create a 3x3 2-D list:
>> py> y = [[0]*3]*3
> py> y
> [[0, 0, 0], [0, 0, 0], [0, 0, 0]]
>>> but alas, it's a trap:
>> py> y[0][0] = 1
> py> y
> [[1, 0, 0], [1, 0, 0], [1, 0, 0]]

Another way of looking at it would be in terms of evaluation rather than
copying. [<stuff>] evaluates to a new list object, so if there were an
alternate version of L * n (for the sake of argument L ** n) that
evaluated the list expression n times to make the new list you would
also get the behaviour you want.
You would also be able to use it in situations like this:
 import random
 [random.randint(1,10)]**6
to get (for example) [2, 4, 7, 1, 1, 8].
Of course, this is just what the [L for _ in range(n)] solution does,
but maybe the situation merits a shorthand?
<snip>
-- 
Ben.