Why lambda in loop requires default?

Sat Mar 26 21:46:08 EDT 2016

Given that Python, like Ruby, is an object-oriented language why doesn't 
this:
def m():
 a = []
 for i in range(3): a.append(lambda: i)
 return a
b = m()
for n in range(3): print(b[n]()) # => 2 2 2
... work the same as this in Ruby:
def m
 a = []
 (0..2).each {|i| a << ->(){i}}
 a
end
aa = m
(0..2).each {|n| puts aa[n].()} # => 0 1 2
lambda i=i: i
... is needed to make it work in Python. Just wondered why?
gvim