Open file in default app and exit in Windows

Wed Jan 28 11:11:12 EST 2015

On 2015年01月28日 07:50, stephen.boulet at gmail.com wrote:
> I am using the following to open a file in its default application
> in Windows 7:
>> from subprocess import call
>> filename = 'my file.csv'
> call('"%s"' % filename, shell=True)

You can try
 import os
 filename = 'my file.csv'
 os.startfile(filename)
which works on Windows systems. For other platforms, you'd have to
manually spawn either "open" on Macs or "xdg-open" on Linux. Not
sure if there's a similar application on the BSDs.
-tkc