Checking homogeneity of Array using List in Python

Mon Aug 26 18:39:02 EDT 2013

On 26 August 2013 14:49, Neil Cerutti <neilc at norwich.edu> wrote:
> On 2013年08月25日, sahil301290 at gmail.com <sahil301290 at gmail.com> wrote:
>>>> eg. my input is ['1', ' ', 'asdasd231231', '1213asasd', '43242']
>> I want it to be interpreted as:
>> [1, [None], [None], [None], 43242]
>>>> NOTE: NO INBUILT FUNCTION BE USED.
>> Impossible. I think.

class BoilerplateToStopCheating:
 def __init__(self):
 """Factor things out to prevent cheating."""
 self.digit_to_number = {"0":0, "1":1, "2":2, "3":3, "4":4,
"5":5, "6":6, "7":7, "8":8, "9":9}
 def __call__(self, items):
 def fudging():
 """More cheat-fudging."""
 for item in items:
 try:
 as_number = 0
 for char in item:
 as_number *= 10
 as_number += self.digit_to_number[char]
 yield as_number
 except KeyError:
 yield [None]
 [*z] = fudging()
 return z
converter = BoilerplateToStopCheating()
# Can't use "print"...
# Erm...
converter(['1', ' ', 'asdasd231231', '1213asasd', '43242'])
# Output: [1, [None], [None], [None], 43242]