How to re-implement the crypt.crypt function?

Sat Mar 10 14:33:36 EST 2012

I'm not searching for a full solution and only want to know how to use hashlib to create a equivalent string like 
crypt.crypt('123456', '6ドル$ds41p/9VMA.BHH0U') returns the string below. 
'6ドル$ds41p/9VMA.BHH0U$yv25s7jLxTRKLDNjIvT0Qc2jbcqdFRi5.PftO3cveTvjK49JhwCarIowOfrrNPD/PpYT3n6oNDIbjAONh8RXt1'
I tried:
from hashlib import sha512
from base64 import b64encode, b64decode
salt='ds41p/9VMA.BHH0U'
pwd='123456'
b64encode( sha512(pwd+salt).digest(), altchars='./' )
b64encode( sha512(salt+pwd).digest(), altchars='./' )
b64encode( sha512( pwd + b64decode(salt, altchars='./') ).digest(), altchars='./')
b64encode( sha512( b64decode(salt, altchars='./') + pwd ).digest(), altchars='./')
of course none of the four returns the value I want, 'yv25s7jLxTRKLDNjIvT0Qc2jbcqdFRi5.PftO3cveTvjK49JhwCarIowOfrrNPD/PpYT3n6oNDIbjAONh8RXt1', how can I get the value? I can't use crypt.crypt because of the consideration of cross-platform.
Thanks,
Cosmia