Of Functions, Objects, and Methods-I NEED HELP PLEASE

Wed Jun 8 16:34:49 EDT 2011

On Wed, Jun 8, 2011 at 1:09 PM, Cathy James <nambo4jb at gmail.com> wrote:
> I am almost there, but I need a little help:
>> I would like to
>> a) print my dogs in the format  index. name: breed as follows:
>> 0. Mimi:Poodle
> 1.Sunny: Beagle
> 2. Bunny: German Shepard
> I am getting
>> (0, ('Mimi', 'Poodle')) . Mimi : Poodle instead-what have I done wrong?
>> b) I would like to append to my list, but my line dogs.dogAppend() is
> giving a TypeError:
>> for i in enumerate (self.dogAppend()):
> TypeError: 'list' object is not callable
>> Any help?
>> #MY CODE BELOW:
>> import sys
> class Dog():
>    def __init__(self, name, breed):
>        self.name = name
>        self.breed = breed
>>    def dogAppend(self):
>        self.dogAppend = []
>        self.dogAppend.append((self.name,self.breed))
>        return self.dogAppend
>
In Python, everything is an object. And when we say everything, we
really do mean everything. A function is an object too. So when you do
self.dogAppend = [], you're replacing self.dogAppend (the function
object) with a list.
>>    def display (self):
>        for i in enumerate (self.dogAppend()):

I don't know what you're trying to do here, because this makes no
sense. dogAppend is going to return a list of a single object, so it's
going to be 0 every time. And enumerate returns two things: the index
and the object. Since you only specified one variable, you get the
tuple of (index, object) which is what you're seeing.
You're supposed to do :
 for i, dog in enumerate(a_list_of_all_the_dogs) :
            print (i,".",  dog.name, ": " + dog.breed)
for what you're trying to get.
>> if __name__ == "__main__":
>    dogs = Dog(name=input (" Enter Dog Name: "), breed=input ("Enter
> Dog Breed: "))
>    while not dogs:
>        print("Goodbye!!")
>        sys.exit()
>    else:
>        #dogs.dogAppend()
>        dogs.display()
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