pyqt unhandled RuntimeError \"no access to protected functions or signals for objects not created from Python

luca72 lucaberto at libero.it
Fri Sep 3 03:58:12 EDT 2010


Hello i have also write to pyqt mailing list but maybe you can help me
to solve this question:
I have write a tcpserver but wheni try to read by the signal
readyRead() e get the error
 this the part of the program:
 def nuova_connessione(self):
 print 'Nuova connessione'
 self.nuovo_socket =
self.mio_server.nextPendingConnection()
 print self.nuovo_socket
 self.connect(self.nuovo_socket,
QtCore.SIGNAL("connected()"), self.
 connessione)
 self.connect(self.nuovo_socket,
QtCore.SIGNAL("readyRead()"), self.
 leggo_risposta)
 self.connect(self.nuovo_socket,
QtCore.SIGNAL("disconnected"), self.
 sconnesso)
 self.connect(self.nuovo_socket,
QtCore.SIGNAL("error(Qtcore.
 QAbsatctSocket::SocketError)"), self.server_errore)
def leggo_risposta(self):
 cosa_leggo = self.nuovo_socket.readData(self.nuovo_socket.
 bytesAvailable())
 can you help me
 Thanks


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