Slicing [N::-1]

Fri Mar 5 21:09:59 EST 2010

On Mar 5, 6:34 pm, Gary Herron <gher... at islandtraining.com> wrote:
> Mensanator wrote:
> > On Mar 5, 3:42 pm, Gary Herron <gher... at islandtraining.com> wrote:
>> >> Mensanator wrote:
>> >>> The only way to get a 0 from a reverse range() is to have a bound of
> >>> -1.
>> >> Not quite.  An empty second bound goes all the way to the zero index:
>> > Not the same thing. You're using the bounds of the slice index.
> > I was refering to the bounds of the range() function.
>> >>>> for a in range(9,-9,-1):print(a,end=' ')
>> > 9 8 7 6 5 4 3 2 1 0 -1 -2 -3 -4 -5 -6 -7 -8
>> > To get that to stop at 0, you use a -1 as the bounds:
>> >>>> for a in range(9,-1,-1):print(a,end=' ')
>> > 9 8 7 6 5 4 3 2 1 0
>> > Your slice notation only works if the last (first?) number in
> > the range happens to be 0. What if the range bounds were variables?
> > You may still want to force the range's last number to be 0 by
> > using a constant like range(a,-1,-1) rather than just take
> > the last number of range(a,b,-1) by using slice notation.
>> All true  and valid of course, but I was just contridicting the "the
> ONLY way to get a 0" (emphasis mine) part of the statement.

Does it still contradict if you do not use the '::' as the OP
requested?
>> Gary Herron
>>>>>> >>  >>> range(9)[2::-1]
> >> [2, 1, 0]
>> >> Gary Herron- Hide quoted text -
>> - Show quoted text -- Hide quoted text -
>> - Show quoted text -