[Python-Dev] Replacement for print in Python 3.0

Thu Sep 8 16:10:19 CEST 2005

Barry Warsaw wrote:
> On Wed, 2005年09月07日 at 08:55, Nick Coghlan wrote:
>>>>The leading 'p' (for 'positional') is necessary to get around the fact that 1ドル 
>>is currently an illegal identifier in a Template
>>> That should be fixable. Ideally, 1ドル is better than $p1.

I also looked into the idea of adding formatting support to the 
string.Template syntax.
Given a reimplementation of string.Template with the following pattern:
 pattern = r"""
 %(delim)s(?:
 (?P<escaped>%(delim)s) | # An escape sequence of two delimiters, or
 (
 (\[(?P<format>[^%%]*)\])? # an optional simple format string,
 (
 (?P<named>%(id)s) | # and a Python identifier, or
 {(?P<braced>%(id)s)} # a braced identifier
 )
 ) |
 (?P<invalid>) # An ill-formed delimiter expr
 )
 """
And "convert" functions modified to use "fmt" where "'%s'" is currently used, 
with "fmt" defined via:
 fmt = mo.group('format')
 if fmt is None:
 fmt = '%s' # Default to simple string format
 else:
 fmt = '%' + fmt
The following works:
Py> t = format.Template("$item: $[0.2f]quantity")
Py> t.format(quantity=0.5, item='Bees')
'Bees: 0.50'
Combining with a 'format' function similar to the one in my previous message, 
and an id pattern modified to permit numbers as identifiers:
Py> format("1ドル: $[0.2f]2", 'Bees', 0.5)
'Bees: 0.50'
Cheers,
Nick.
-- 
Nick Coghlan | ncoghlan at gmail.com | Brisbane, Australia
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