[Python-Dev] Replacement for print in Python 3.0

Sat Sep 3 15:35:58 CEST 2005

On 9/3/05, Nick Coghlan <ncoghlan at gmail.com> wrote:
[...]
> Playing well with generator expressions comes for free, too:
>> print " ".join(str(x*x) for x in range(10))
> => output(*(x*x for x in range(10)))

Hmm... This prompts a coding question - is it possible to recognise
which arguments to a function are generators, so that you could write
 output(1, 2, [3,4], (c for c in 'abc'), 'def', (5, 6))
and get
 1 2 [3, 4] a b c def (5, 6)
?
At the simplest level, an explicit check for types.GeneratorType would
work, but I'm not sure if there's a more general check that might
might work - for example, iter((1,2,3)) may be a candidate for looping
over, where (1,2,3) clearly (? :-)) isn't. Maybe "iter(arg) is arg" is
the right check...
Of course, there's a completely separate question as to whether magic
this subtle is *advisable*...
Paul.