[Python-checkins] python/dist/src/Lib _strptime.py, 1.23.4.6,
1.23.4.7
bcannon at users.sourceforge.net
bcannon at users.sourceforge.net
Thu Oct 28 06:50:30 CEST 2004
Update of /cvsroot/python/python/dist/src/Lib
In directory sc8-pr-cvs1.sourceforge.net:/tmp/cvs-serv32106/Lib
Modified Files:
Tag: release23-maint
_strptime.py
Log Message:
Backport of fix for bug of year/<week of year>/<day of week> calculation that
didn't handle %U for years starting on Monday.
Index: _strptime.py
===================================================================
RCS file: /cvsroot/python/python/dist/src/Lib/_strptime.py,v
retrieving revision 1.23.4.6
retrieving revision 1.23.4.7
diff -u -d -r1.23.4.6 -r1.23.4.7
--- _strptime.py 18 Oct 2004 01:56:16 -0000 1.23.4.6
+++ _strptime.py 28 Oct 2004 04:50:28 -0000 1.23.4.7
@@ -518,25 +518,27 @@
# If we know the week of the year and what day of that week, we can figure
# out the Julian day of the year
# Calculations below assume 0 is a Monday
- if julian == -1 and week_of_year != -1 and weekday != -1 and year != -1:
- # Adjust for U directive so that calculations are not dependent on
- # directive used to figure out week of year
- if weekday == 6 and week_of_year_start == 6:
- week_of_year -= 1
- # For some reason when Dec 31 falls on a Monday the week of the year is
- # off by a week; verified on both OS X and Solaris.
- elif weekday == 0 and week_of_year_start == 6 and week_of_year >= 52:
- week_of_year += 1
+ if julian == -1 and week_of_year != -1 and weekday != -1:
# Calculate how many days in week 0
first_weekday = datetime_date(year, 1, 1).weekday()
preceeding_days = 7 - first_weekday
if preceeding_days == 7:
preceeding_days = 0
+ # Adjust for U directive so that calculations are not dependent on
+ # directive used to figure out week of year
+ if weekday == 6 and week_of_year_start == 6:
+ week_of_year -= 1
+ # If a year starts and ends on a Monday but a week is specified to
+ # start on a Sunday we need to up the week to counter-balance the fact
+ # that with %W that first Monday starts week 1 while with %U that is
+ # week 0 and thus shifts everything by a week
+ if weekday == 0 and first_weekday == 0 and week_of_year_start == 6:
+ week_of_year += 1
# If in week 0, then just figure out how many days from Jan 1 to day of
# week specified, else calculate by multiplying week of year by 7,
# adding in days in week 0, and the number of days from Monday to the
# day of the week
- if not week_of_year:
+ if week_of_year == 0:
julian = 1 + weekday - first_weekday
else:
days_to_week = preceeding_days + (7 * (week_of_year - 1))
More information about the Python-checkins
mailing list