netbsd-help: Re: shell question...

Subject: Re: shell question...
To: None <netbsd-help@netbsd.org>
From: Jukka Salmi <j+nbsd@2006.salmi.ch>
List: netbsd-help
Date: 01/31/2006 17:19:32

Chuck Swiger --> netbsd-help (2006年01月31日 10:53:15 -0500):
> Jukka Salmi wrote:
> [ ... ]
> > 	[1] 6980
> > 
> > I guess it's the shell who prints these strings, isn't it? If yes, is
> > there a way to suppress this output?
> 
> Yes, it is the shell that produces that output.
> 
> You can suppress the output by having the process disassociate itself from the
> shell's process group and tty. Most daemons will do so automaticly (see "man 3
> daemon", "man 8 daemon"), and some shells have a "disown" primitive which will
> disown a backgrounded task.
I see. Hmm, the program I want to run in the background is itself a
shell script, and the shell doesn't seem to have such a disown
primitive.
Is it possible to do something like daemon(3) in shell? I tried with
putting
	cd /
	exec <&-
	exec >&-
	exec 2>&-
to the top of my script, but this seems not to be enough...
Regards, Jukka
-- 
bashian roulette:
$ ((RANDOM%6)) || rm -rf ~