On 06/23/2020 09:01 AM, Guido van Rossum wrote:
PEP 622
Okay, I took Paul Moore's advice and went looking in existing code for some examples, and came across the following: if isinstance(v, int): # v is an offset elif isinstance(v, str): # v is a docstring elif isinstance(v, tuple) and len(v) in (2, 3) and isinstance(v[0], baseinteger) and isinstance(v[1], (basestring, NoneType)): # v is an offset, a docstring, and (maybe) a default elif isinstance(v, tuple) and len(v) in (1, 2) and isinstance(v[0], (basestring, NoneType)): # v is a docstring and (maybe) a default That seems like it would be a perfect match (hah) for the new syntax, but I am not confident in my efforts. This is what I started with: match v: # goal here is to turn v into an (offset, docstring, default value) case int: v = v, None, None case str: v = None, v, None case (str, ): # how to combine with above case? v = None, v[0], None case (int, str): v += (None, ) case (int, str, default): pass case (str, default): v = None, v[0], v[1] Which got me to here: match v: # goal here is to turn v into an (offset, docstring, default value) case int(offset): v = offset, None, None case str(doc) | (str(doc), ): v = None, doc, None case (int(offset), str(doc)): v = offset, doc, None case (int(offset), str(doc), default): # already correct pass case (str(doc), default): v = None, doc, default Is this correct? Side note: I would much rather read "case str(doc) or (str(doc), )" instead of a |. -- ~Ethan~ _______________________________________________ Python-Dev mailing list -- [email protected] To unsubscribe send an email to [email protected] https://mail.python.org/mailman3/lists/python-dev.python.org/ Message archived at https://mail.python.org/archives/list/[email protected]/message/N6XLWOSRAVUF6MOOQFZTVQHXEWFRXTHY/ Code of Conduct: http://python.org/psf/codeofconduct/