On 5/27/2019 3:18 AM, Greg Ewing wrote:
Chris Angelico wrote:
Except that it does. After calling locals() a second time, the result
of the *first* call will be updated to reflect changes.
Yeow. That's *really* unintuitive. There had better be an extremely
good reason for this behaviour.
I believe that the situation is or can be thought of as this: there is
exactly 1 function locals dict. Initially, it is empty and inaccessible
(unusable) from code. Each locals() call updates the dict to a current
snapshot and returns it.
--
Terry Jan Reedy
_______________________________________________
Python-Dev mailing list
[email protected]
https://mail.python.org/mailman/listinfo/python-dev
Unsubscribe:
https://mail.python.org/mailman/options/python-dev/archive%40mail-archive.com