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feat: update lc problems (doocs#3491)
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‎solution/0000-0099/0024.Swap Nodes in Pairs/README_EN.md‎

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<p>&nbsp;</p>
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<p><strong class="example">Example 1:</strong></p>
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<img alt="" src="https://fastly.jsdelivr.net/gh/doocs/leetcode@main/solution/0000-0099/0024.Swap%20Nodes%20in%20Pairs/images/swap_ex1.jpg" style="width: 422px; height: 222px;" />
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<pre>
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<strong>Input:</strong> head = [1,2,3,4]
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<strong>Output:</strong> [2,1,4,3]
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</pre>
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<div class="example-block">
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<p><strong>Input:</strong> <span class="example-io">head = [1,2,3,4]</span></p>
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<p><strong>Output:</strong> <span class="example-io">[2,1,4,3]</span></p>
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<p><strong>Explanation:</strong></p>
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<p><img alt="" src="https://fastly.jsdelivr.net/gh/doocs/leetcode@main/solution/0000-0099/0024.Swap%20Nodes%20in%20Pairs/images/swap_ex1.jpg" style="width: 422px; height: 222px;" /></p>
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</div>
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<p><strong class="example">Example 2:</strong></p>
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<pre>
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<strong>Input:</strong> head = []
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<strong>Output:</strong> []
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</pre>
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<div class="example-block">
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<p><strong>Input:</strong> <span class="example-io">head = []</span></p>
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<p><strong>Output:</strong> <span class="example-io">[]</span></p>
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</div>
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<p><strong class="example">Example 3:</strong></p>
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<pre>
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<strong>Input:</strong> head = [1]
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<strong>Output:</strong> [1]
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</pre>
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<div class="example-block">
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<p><strong>Input:</strong> <span class="example-io">head = [1]</span></p>
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<p><strong>Output:</strong> <span class="example-io">[1]</span></p>
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</div>
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<p><strong class="example">Example 4:</strong></p>
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<div class="example-block">
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<p><strong>Input:</strong> <span class="example-io">head = [1,2,3]</span></p>
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<p><strong>Output:</strong> <span class="example-io">[2,1,3]</span></p>
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</div>
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<p>&nbsp;</p>
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<p><strong>Constraints:</strong></p>

‎solution/0000-0099/0049.Group Anagrams/README_EN.md‎

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<!-- description:start -->
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<p>Given an array of strings <code>strs</code>, group <strong>the anagrams</strong> together. You can return the answer in <strong>any order</strong>.</p>
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<p>An <strong>Anagram</strong> is a word or phrase formed by rearranging the letters of a different word or phrase, typically using all the original letters exactly once.</p>
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<p>Given an array of strings <code>strs</code>, group the <span data-keyword="anagram">anagrams</span> together. You can return the answer in <strong>any order</strong>.</p>
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<p>&nbsp;</p>
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<p><strong class="example">Example 1:</strong></p>
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<pre><strong>Input:</strong> strs = ["eat","tea","tan","ate","nat","bat"]
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<strong>Output:</strong> [["bat"],["nat","tan"],["ate","eat","tea"]]
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</pre><p><strong class="example">Example 2:</strong></p>
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<pre><strong>Input:</strong> strs = [""]
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<strong>Output:</strong> [[""]]
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</pre><p><strong class="example">Example 3:</strong></p>
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<pre><strong>Input:</strong> strs = ["a"]
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<strong>Output:</strong> [["a"]]
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</pre>
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<div class="example-block">
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<p><strong>Input:</strong> <span class="example-io">strs = [&quot;eat&quot;,&quot;tea&quot;,&quot;tan&quot;,&quot;ate&quot;,&quot;nat&quot;,&quot;bat&quot;]</span></p>
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<p><strong>Output:</strong> <span class="example-io">[[&quot;bat&quot;],[&quot;nat&quot;,&quot;tan&quot;],[&quot;ate&quot;,&quot;eat&quot;,&quot;tea&quot;]]</span></p>
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<p><strong>Explanation:</strong></p>
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<ul>
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<li>There is no string in strs that can be rearranged to form <code>&quot;bat&quot;</code>.</li>
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<li>The strings <code>&quot;nat&quot;</code> and <code>&quot;tan&quot;</code> are anagrams as they can be rearranged to form each other.</li>
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<li>The strings <code>&quot;ate&quot;</code>, <code>&quot;eat&quot;</code>, and <code>&quot;tea&quot;</code> are anagrams as they can be rearranged to form each other.</li>
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</ul>
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</div>
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<p><strong class="example">Example 2:</strong></p>
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<div class="example-block">
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<p><strong>Input:</strong> <span class="example-io">strs = [&quot;&quot;]</span></p>
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<p><strong>Output:</strong> <span class="example-io">[[&quot;&quot;]]</span></p>
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</div>
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<p><strong class="example">Example 3:</strong></p>
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<div class="example-block">
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<p><strong>Input:</strong> <span class="example-io">strs = [&quot;a&quot;]</span></p>
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<p><strong>Output:</strong> <span class="example-io">[[&quot;a&quot;]]</span></p>
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</div>
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<p>&nbsp;</p>
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<p><strong>Constraints:</strong></p>
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‎solution/0000-0099/0071.Simplify Path/README.md‎

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<!-- description:start -->
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<p>给你一个字符串 <code>path</code> ,表示指向某一文件或目录的&nbsp;Unix 风格 <strong>绝对路径 </strong>(以 <code>'/'</code> 开头),请你将其转化为更加简洁的规范路径。</p>
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<p>给你一个字符串 <code>path</code> ,表示指向某一文件或目录的&nbsp;Unix 风格 <strong>绝对路径 </strong>(以 <code>'/'</code> 开头),请你将其转化为 <strong>更加简洁的规范路径</strong>。</p>
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<p class="MachineTrans-lang-zh-CN">在 Unix 风格的文件系统中,一个点(<code>.</code>)表示当前目录本身;此外,两个点 (<code>..</code>)&nbsp;表示将目录切换到上一级(指向父目录);两者都可以是复杂相对路径的组成部分。任意多个连续的斜杠(即,<code>'//'</code>)都被视为单个斜杠 <code>'/'</code> 。 对于此问题,任何其他格式的点(例如,<code>'...'</code>)均被视为文件/目录名称。</p>
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<p class="MachineTrans-lang-zh-CN">在 Unix 风格的文件系统中规则如下:</p>
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<p>请注意,返回的 <strong>规范路径</strong> 必须遵循下述格式:</p>
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<ul>
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<li class="MachineTrans-lang-zh-CN">一个点&nbsp;<code>'.'</code>&nbsp;表示当前目录本身。</li>
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<li class="MachineTrans-lang-zh-CN">此外,两个点 <code>'..'</code>&nbsp;表示将目录切换到上一级(指向父目录)。</li>
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<li class="MachineTrans-lang-zh-CN">任意多个连续的斜杠(即,<code>'//'</code>&nbsp;或 <code>'///'</code>)都被视为单个斜杠 <code>'/'</code>。</li>
28+
<li class="MachineTrans-lang-zh-CN">任何其他格式的点(例如,<code>'...'</code>&nbsp;或 <code>'....'</code>)均被视为有效的文件/目录名称。</li>
29+
</ul>
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<p>返回的 <strong>简化路径</strong> 必须遵循下述格式:</p>
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<ul>
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<li>始终以斜杠 <code>'/'</code> 开头。</li>
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<p><strong class="example">示例 1:</strong></p>
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<div class="example-block">
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<p><span class="example-io"><b>输入:</b>path = "/home/"</span></p>
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<p><strong>输入:</strong><span class="example-io">path = "/home/"</span></p>
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<p><span class="example-io"><b>输出:</b>"/home"</span></p>
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<p><strong>解释:</strong></p>
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<p>应删除尾部斜杠。</p>
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<p>应删除尾随斜杠。</p>
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</div>
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<p><strong class="example">示例 2:</strong></p>
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<div class="example-block">
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<p><span class="example-io"><b>输入:</b></span><spanclass="example-io">path = "/home//foo/"</span></p>
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<p><span class="example-io"><b>输入:</b>path = "/home//foo/"</span></p>
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<p><span class="example-io"><b>输出:</b></span><spanclass="example-io">"/home/foo"</span></p>
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<p><span class="example-io"><b>输出:</b>"/home/foo"</span></p>
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<p><strong>解释:</strong></p>
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<p><strong class="example">示例 3:</strong></p>
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<div class="example-block">
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<p><spanclass="example-io"><b>输入:</b></span><span class="example-io">path = "/home/user/Documents/../Pictures"</span></p>
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<p><strong>输入:</strong><span class="example-io">path = "/home/user/Documents/../Pictures"</span></p>
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<p><span class="example-io"><b>输出:</b></span><spanclass="example-io">"/home/user/Pictures"</span></p>
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<p><span class="example-io"><b>输出:</b>"/home/user/Pictures"</span></p>
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<p><strong>解释:</strong></p>
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<p>两个点&nbsp;<code>".."</code>&nbsp;表示上一级目录。</p>
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<p>两个点&nbsp;<code>".."</code>&nbsp;表示上一级目录(父目录)。</p>
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</div>
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<p><strong class="example">示例 4:</strong></p>
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<div class="example-block">
76-
<p><span class="example-io"><b>输入:</b></span><spanclass="example-io">path = "/../"</span></p>
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<p><span class="example-io"><b>输入:</b>path = "/../"</span></p>
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<p><span class="example-io"><b>输出:</b></span><spanclass="example-io">"/"</span></p>
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<p><span class="example-io"><b>输出:</b>"/"</span></p>
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<p><strong>解释:</strong></p>
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<p>不可能从根目录上升级一级。</p>
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<p>不可能从根目录上升一级目录。</p>
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</div>
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<p><strong class="example">示例 5:</strong></p>
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<div class="example-block">
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<p><span class="example-io"><b>输入:</b></span><spanclass="example-io">path = "/.../a/../b/c/../d/./"</span></p>
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<p><span class="example-io"><b>输入:</b>path = "/.../a/../b/c/../d/./"</span></p>
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<p><span class="example-io"><b>输出:</b></span><spanclass="example-io">"/.../b/d"</span></p>
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<p><span class="example-io"><b>输出:</b>"/.../b/d"</span></p>
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<p><strong>解释:</strong></p>
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<p><code>"..."</code> 是此问题中目录的有效名称。</p>
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<p><code>"..."</code>&nbsp;在这个问题中是一个合法的目录名。</p>
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</div>
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<p>&nbsp;</p>

‎solution/0000-0099/0071.Simplify Path/README_EN.md‎

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<!-- description:start -->
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<p>Given an absolute path for a Unix-style file system, which begins with a slash <code>&#39;/&#39;</code>, transform this path into its <strong>simplified canonical path</strong>.</p>
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<p>You are given an <em>absolute</em> path for a Unix-style file system, which always begins with a slash <code>&#39;/&#39;</code>. Your task is to transform this absolute path into its <strong>simplified canonical path</strong>.</p>
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<p>In Unix-style file system context, a single period <code>&#39;.&#39;</code> signifies the current directory, a double period <code>&quot;..&quot;</code> denotes moving up one directory level, and multiple slashes such as <code>&quot;//&quot;</code> are interpreted as a single slash. In this problem, treat sequences of periods not covered by the previous rules (like <code>&quot;...&quot;</code>) as valid names for files or directories.</p>
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<p>The <em>rules</em> of a Unix-style file system are as follows:</p>
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<p>The simplified canonical path should adhere to the following rules:</p>
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<ul>
25+
<li>A single period <code>&#39;.&#39;</code> represents the current directory.</li>
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<li>A double period <code>&#39;..&#39;</code> represents the previous/parent directory.</li>
27+
<li>Multiple consecutive slashes such as <code>&#39;//&#39;</code> and <code>&#39;///&#39;</code> are treated as a single slash <code>&#39;/&#39;</code>.</li>
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<li>Any sequence of periods that does <strong>not match</strong> the rules above should be treated as a <strong>valid directory or</strong> <strong>file </strong><strong>name</strong>. For example, <code>&#39;...&#39; </code>and <code>&#39;....&#39;</code> are valid directory or file names.</li>
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</ul>
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<p>The simplified canonical path should follow these <em>rules</em>:</p>
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<ul>
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<li>It must start with a single slash <code>&#39;/&#39;</code>.</li>
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<li>Directories within the path should be separated by only one slash <code>&#39;/&#39;</code>.</li>
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<li>It should not end with a slash <code>&#39;/&#39;</code>, unless it&#39;s the root directory.</li>
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<li>It should exclude any single or double periods used to denote current or parent directories.</li>
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<li>The path must start with a single slash <code>&#39;/&#39;</code>.</li>
35+
<li>Directories within the path must be separated by exactly one slash <code>&#39;/&#39;</code>.</li>
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<li>The path must not end with a slash <code>&#39;/&#39;</code>, unless it is the root directory.</li>
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<li>The path must not have any single or double periods (<code>&#39;.&#39;</code> and <code>&#39;..&#39;</code>) used to denote current or parent directories.</li>
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</ul>
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<p>Return the new path.</p>
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<p>Return the <strong>simplified canonical path</strong>.</p>
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<p>&nbsp;</p>
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<p><strong class="example">Example 1:</strong></p>
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<p><strong>Explanation:</strong></p>
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<p>A double period <code>&quot;..&quot;</code> refers to the directory up a level.</p>
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<p>A double period <code>&quot;..&quot;</code> refers to the directory up a level (the parent directory).</p>
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</div>
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<p><strong class="example">Example 4:</strong></p>

‎solution/0200-0299/0217.Contains Duplicate/README.md‎

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<p>&nbsp;</p>
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<p><strong>示例 1:</strong></p>
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<p><strongclass="example">示例 1:</strong></p>
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<pre>
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<strong>输入:</strong>nums = [1,2,3,1]
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<strong>输出:</strong>true</pre>
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<div class="example-block">
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<p><span class="example-io"><b>输入:</b>nums = [1,2,3,1]</span></p>
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<p><strong>示例 2:</strong></p>
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<p><spanclass="example-io"><b>输出:</b>true</span></p>
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<pre>
34-
<strong>输入:</strong>nums = [1,2,3,4]
35-
<strong>输出:</strong>false</pre>
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<p><strong>解释:</strong></p>
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<p><strong>示例&nbsp;3:</strong></p>
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<p>元素 1 在下标 0 和 3 出现。</p>
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</div>
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<pre>
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<strong>输入:</strong>nums = [1,1,1,3,3,4,3,2,4,2]
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<strong>输出:</strong>true</pre>
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<p><strong class="example">示例 2:</strong></p>
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<div class="example-block">
40+
<p><span class="example-io"><b>输入:</b>nums = [1,2,3,4]</span></p>
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<p><span class="example-io"><b>输出:</b>false</span></p>
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<p><strong>解释:</strong></p>
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<p>所有元素都不同。</p>
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</div>
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<p><strong class="example">示例 3:</strong></p>
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<div class="example-block">
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<p><span class="example-io"><b>输入:</b>nums = [1,1,1,3,3,4,3,2,4,2]</span></p>
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<p><span class="example-io"><b>输出:</b>true</span></p>
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</div>
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<p>&nbsp;</p>
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‎solution/0200-0299/0217.Contains Duplicate/README_EN.md‎

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<p>&nbsp;</p>
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<p><strong class="example">Example 1:</strong></p>
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<pre><strong>Input:</strong> nums = [1,2,3,1]
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<strong>Output:</strong> true
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</pre><p><strong class="example">Example 2:</strong></p>
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<pre><strong>Input:</strong> nums = [1,2,3,4]
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<strong>Output:</strong> false
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</pre><p><strong class="example">Example 3:</strong></p>
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<pre><strong>Input:</strong> nums = [1,1,1,3,3,4,3,2,4,2]
32-
<strong>Output:</strong> true
33-
</pre>
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<div class="example-block">
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<p><strong>Input:</strong> <span class="example-io">nums = [1,2,3,1]</span></p>
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<p><strong>Output:</strong> <span class="example-io">true</span></p>
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<p><strong>Explanation:</strong></p>
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<p>The element 1 occurs at the indices 0 and 3.</p>
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</div>
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<p><strong class="example">Example 2:</strong></p>
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<div class="example-block">
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<p><strong>Input:</strong> <span class="example-io">nums = [1,2,3,4]</span></p>
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<p><strong>Output:</strong> <span class="example-io">false</span></p>
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<p><strong>Explanation:</strong></p>
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<p>All elements are distinct.</p>
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</div>
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<p><strong class="example">Example 3:</strong></p>
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<div class="example-block">
51+
<p><strong>Input:</strong> <span class="example-io">nums = [1,1,1,3,3,4,3,2,4,2]</span></p>
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<p><strong>Output:</strong> <span class="example-io">true</span></p>
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</div>
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<p>&nbsp;</p>
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<p><strong>Constraints:</strong></p>
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‎solution/0200-0299/0242.Valid Anagram/README.md‎

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<!-- description:start -->
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<p>给定两个字符串 <code><em>s</em></code> 和 <code><em>t</em></code> ,编写一个函数来判断 <code><em>t</em></code> 是否是 <code><em>s</em></code> 的字母异位词。</p>
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<p><strong>字母异位词</strong> 是通过重新排列不同单词或短语的字母而形成的单词或短语,通常只使用所有原始字母一次。</p>
21+
<p>给定两个字符串 <code>s</code> 和 <code>t</code> ,编写一个函数来判断 <code>t</code> 是否是 <code>s</code> 的 <span data-keyword="anagram">字母异位词</span>。</p>
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<p>&nbsp;</p>
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<p><strong>示例&nbsp;1:</strong></p>
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<pre>
30-
<strong>输入:</strong> <em>s</em> = "anagram", <em>t</em> = "nagaram"
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<strong>输入:</strong> s = "anagram", t = "nagaram"
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<strong>输出:</strong> true
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</pre>
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<p><strong>示例 2:</strong></p>
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<pre>
37-
<strong>输入:</strong> <em>s</em> = "rat", <em>t</em> = "car"
35+
<strong>输入:</strong> s = "rat", t = "car"
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<strong>输出: </strong>false</pre>
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<p>&nbsp;</p>

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