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Commit 3819e2a

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add LeetCode 257. 二叉树的所有路径
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![](https://imgconvert.csdnimg.cn/aHR0cHM6Ly9jZG4uanNkZWxpdnIubmV0L2doL2Nob2NvbGF0ZTE5OTkvY2RuL2ltZy8yMDIwMDgyODE0NTUyMS5qcGc?x-oss-process=image/format,png)
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>仰望星空的人,不应该被嘲笑
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## 题目描述
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给定一个二叉树,返回所有从根节点到叶子节点的路径。
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说明: 叶子节点是指没有子节点的节点。
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示例:
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```javascript
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输入:
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1
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/ \
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2 3
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\
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5
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输出: ["1->2->5", "1->3"]
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解释: 所有根节点到叶子节点的路径为: 1->2->5, 1->3
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```
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来源:力扣(LeetCode)
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链接:https://leetcode-cn.com/problems/binary-tree-paths
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著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。
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## 解题思路
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`dfs`,从根节点开始搜,对于非叶子节点,进行累计,如果找到了叶子节点,我们就将结果存起来。通过字符串拼接来存储路径。
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```javascript
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/**
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* Definition for a binary tree node.
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* function TreeNode(val) {
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* this.val = val;
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* this.left = this.right = null;
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* }
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*/
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/**
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* @param {TreeNode} root
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* @return {string[]}
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*/
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var binaryTreePaths = function (root) {
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if (root == null) return [];
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let res = [];
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let dfs = (cur, root) => {
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// 叶子节点,存起来
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if (root.left == null && root.right == null) {
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cur += root.val;
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res.push(cur);
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return;
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}
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cur += root.val + '->'; // 处理非叶子节点
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// 先遍历左子树,再遍历右子树
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root.left && dfs(cur, root.left);
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root.right && dfs(cur, root.right);
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}
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dfs('', root);
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return res;
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};
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```
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## 最后
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文章产出不易,还望各位小伙伴们支持一波!
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往期精选:
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<a href="https://github.com/Chocolate1999/Front-end-learning-to-organize-notes">小狮子前端の笔记仓库</a>
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<a href="https://github.com/Chocolate1999/leetcode-javascript">leetcode-javascript:LeetCode 力扣的 JavaScript 解题仓库,前端刷题路线(思维导图)</a>
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小伙伴们可以在Issues中提交自己的解题代码,🤝 欢迎Contributing,可打卡刷题,Give a ⭐️ if this project helped you!
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<a href="https://yangchaoyi.vip/">访问超逸の博客</a>,方便小伙伴阅读玩耍~
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![](https://img-blog.csdnimg.cn/2020090211491121.png#pic_center)
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```javascript
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学如逆水行舟,不进则退
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```
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