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Coding SOlution of symmetric tree

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Original file line number	Diff line number	Diff line change
`@@ -1,9 +1,17 @@`
	`1`	`+'''`
	`2`	`+ Given the root of a binary tree, check whether it is a mirror of itself (i.e., symmetric around its center).`
	`3`	`+`
	`4`	`+`
	`5`	`+'''`
	`6`	`+`
	`7`	`+`
`1`	`8`	`# Definition for a binary tree node.`
`2`	`9`	`# class TreeNode:`
`3`	`10`	`# def __init__(self, val=0, left=None, right=None):`
`4`	`11`	`# self.val = val`
`5`	`12`	`# self.left = left`
`6`	`13`	`# self.right = right`
	`14`	`+`
`7`	`15`	`class Solution:`
`8`	`16`	`def isSymmetric(self, root: Optional[TreeNode]) -> bool:`
`9`	`17`	`def isMirror(root1, root2):`

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